Answer:
~91 chirps/min
Step-by-step explanation:
This exercise is asking us to estimate based on the values in the table. If we know the temperature is 65°F, let's find the closest values given to interpolate (assuming the data is fairly linear, which it appears to be).
Looks like the closest ones are 60° and 68°. We will look at their corresponding chirps/min and guess a number in between those two.
60° -> 81 chirps/min
68° -> 97 chirps/min
Because 65 is closer to 68 than 60, we expect our result to be closer to 97 than 81.
slope = rise/run
= = 2 chirps/min/°F. So for every °F increase, we expect to increase by 2 chirps/min.
60+5 = 65, so let's add 2*5 = 10 chirps/min to 60 to get 91 chirps/min. This corresponds with what we would have guessed.
8x3 + 8x2 + 4x − 3
8x3 − 34x2 + 25x − 3
8x3 − 42x2 + 25x − 3
Find the product of (4x − 3)(2x2 − 7x + 1).
Answer:
8x3 − 34x2 + 25x − 3
(Took the exam)
12
300
18.75
33.33
Answer:
The answer to your question is 12
Step-by-step explanation:
Use proportion to solve this problem
Equation
Substitution
25x = 15(20)
25x = 300
x = 300 / 25
x = 12
x = JH = 12
Answer:
the correct answer is option A. 12