Burning gasoline in a car affects the

Answers

Answer 1
Answer: Burning gasoline in a car affects the "Enviorment". Hope this helped!

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The distance between Eagle Lake and Swallow Lake on a map is 9 cm. The scale of the map is 4 cm = 2 km.What is the actual distance between Eagle Lake and Swallow Lake?OA. 4.5 kmOB. 5.5 kmOC. 18 kmOD. 72 km
50 POINTS! (I rlly need help)(ALGEBRA 1)
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between the largest and smallest possible measures of the area given this possible error?

Answers

If I understood the question correctly, the answer would be 400

A basketball has a diameter of 9.5cm.

Which of the expressions shows how to determine the volume of air the basketball can hold?

A
34π(4.75)3

B
34π(9.5)3

C
43π(4.75)3

D
43π(

Answers

Answer:

C. (4)/(3)\pi\cdot(4.75)^3\ cm^3

Step-by-step explanation:

The volume of the ball with radius R can be calculated using formula

V=(4)/(3)\pi R^3

A basketball has a diameter of 9.5 cm, so its radius is

R=(D)/(2)=(9.5)/(2)=4.75\ cm

Hence, the volume of air the basketball can hold is

V=(4)/(3)\pi\cdot(4.75)^3\ cm^3

Answer:

I also think it's 4/3 ( 4.75 ) 3

Maddy wrote a pattern starting at 3 and following the rule "add 2.". Ted wrote a pattern starting at 0 and following the rule "add 4."

Answers

Answer:

whats the question


Step-by-step explanation:


Answer:I don't know maybe 7 tell me if it is right


Step-by-step explanation:


Kaynard's first step in solving this rational equation is to simplify it by multiplying both sides by a common denominator. Which is the simplest expression he can use to do this?

Answers

x^2 - 9 = (x + 3)(x -3)

3x - 9 = 3(x - 3)

and

6

Common denominator would be 6(x+3)(x - 3)

Answer: 6(x+3)(x - 3)

PLEASE HELP ASAPPP !!!

Answers

Step-by-step explanation:

Given the function

f\left(x\right)=(1)/(2)\cdot 2^x

  • Putting x = -2

(1)/(2)\cdot \:2^(-2)=(1)/(2)\cdot (1)/(4)=(1)/(8)

so

(x, f(x)) will be (-2, 1/8)

  • Putting x = -1

(1)/(2)\cdot \:\:2^(-1)=(1)/(2)\cdot \:(1)/(2)=(1)/(4)

so

(x, f(x)) will be (-1, 1/4)

  • Putting x = 0

(1)/(2)\cdot \:2^0=(1)/(2)

so

(x, f(x)) will be (0, 1/2)

  • Putting x = 1

(1)/(2)\cdot \:\:2^1=2\cdot \:(1)/(2)=1

so

(x, f(x)) will be (1, 1)

  • Putting x = 2

(1)/(2)\cdot \:\:2^2=4\cdot \:(1)/(2)=2

so

(x, f(x)) will be (2, 2)

The graph is also attached below.

If r(x) = 2 – x2 and w(x) = x – 2, what is the range of (w.r) (x)?

Answers

For this case we have by definition that:

(f * g) (x) = f (x) * g (x)

In this case we must find (w* r) (x), so:

(w * r) (x) = w (x) * r (x) = (x-2) (2-x ^ 2) =

We must apply distributive property that states that:

(a + b) (c + d) = ac + ad + bc + bd

So:

(x-2) (2-x ^ 2) = 2x-x ^ 3-4 + 2x ^ 2 = -x ^ 3 + 2x ^ 2 + 2x-4

The range is the set of all "y" values

 Valid That is to say: (-∞,∞)

Answer:

(-∞,∞)