642×50 2 Digit By 3 digit really bad at math sorry

Answers

Answer 1
Answer: The answer is 32,100. Don't worry practise will make you better!
Answer 2
Answer: the answer would be 32100 

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Solve the following equation:A) y = 1/2 B) y = 2/7 C) y = -2/5 D) y = 3/4 Correct answer: A
The mapping shows a relationship between input and output values. Which ordered pair could be removed to make this relation a function? (–5, 0) (–1, –3) (4, –2) (6, –1)
I need an answer fast

Use the equation y= -2+1. complete each problem(0,_)      (-5,_)      (20,_)      (-68,_)

Answers

1, 11, -39, 137 using the formula

Please help asap its due in one minuteLarry’s Landscaping charges $235 for spring cleanups and $30 for weekly lawn maintenance. Joe’s Landscaping charges $185 for spring cleanups and $35 for weekly lawn maintenance. The system that models this situation is given, where c is the cost of lawn maintenance and w is the number of weeks.
c = 235 + 30w
c = 185 + 35w
The solution to the system is (10, 535).
Which interpretation correctly describes the solution to the system of equations?
a. Larry’s Landscaping will charge more money on the tenth week by charging $535.
b. Joe’s Landscaping will charge more money on the tenth week by charging $535.
c. The cost for lawn maintenance is the same, $535, for both landscaping companies after 10 wk.
d. A customer can have his or her lawn maintained for a maximum of 10 wk. The customer will pay a total of $535.

Answers

The first thing you would do is substitute the 10 in for 'w' and 535 in for 'c'. 
535 = 235 + 30(10)
535 = 185 + 35(10)
Then, you would just solve the equations.
535 = 235 + 30(10)
30(10) = 300
300 + 235 = 535 
So the first equation is true, and we know for a fact that Larry's Landscaping charges $535 for a spring cleaning and weekly yard maintenance for 10 weeks.
On to the next equation.
535 = 185 + 35(10)
35(10) = 350
185 + 350 = 535
So, the second equation is true also. And we also know for a fact that Joe's Landscaping charges $535 for a spring cleaning and weekly yard maintenance for 10 weeks. 
So, now that we know that they will end up charging the same amount of money for a spring cleaning and weekly yard maintenance, the only answer that fits that is C. The cost for lawn maintenance is the same, $535, for both landscaping companies after 10 weeks.
Hope this helps!

535 for both in ten weeks sorry if I am lake took a while to think.

Please help me vote you brainiest

Answers

Answer:

1/5 = 0.2 so, she can drink 0.1 of a gallon each day

to turn a fraction into a decimal you should do..

1/5 since 5 can't go into 1 you add a 0 to the 1 making it a 10 and move the decimal point, since 5 goes into 10, 2 times, we get 0.2

Name the shaded angle in three different ways

Answers

Answer:

1. "angle HGJ" or "angle JGH" (∠HGJ or ∠JGH)

2. "angle G" (∠G)

3. "angle 3" (∠3)

Step-by-step explanation:

Three ways the shaded angle can be named:

1. We can use capital letters to name the shaded angle. The middle letter indicates the vertex. Thus, we would name the shaded angle as: "angle HGJ" or "angle JGH". G is the middle letter, which indicates the vertex of the angle. Most often, the symbol "∠" is usually used to represent the word "angle". In short form, the shaded angle can be named as:

"∠ HGJ" or "∠ JGH"

2. The shaded angle can also be named according to the vertex. Thus, G is the vertex. The angle can be named "angle G" or "∠G"

3. Numbers can be placed at the vertex of the angle, and named accordingly. Thus, the shaded angle of which the vertex is labelled "3" can be named as "angle 3" or "∠3"

26 students in a hostel have provisions for 60 days if 10 more student are admitted to the hostel for how many days would the provisions be enough?​

Answers

Answer:

About 43 days

Step-by-step explanation:

Let's assume that the provisions in the hostel are consumed at a constant rate by each student per day. To find out how long the provisions would last with an additional 10 students, we need to consider the total number of students after the new admissions.

Initially, there are 26 students, and the provisions last for 60 days. Therefore, the total provision "student-days" is 26 students multiplied by 60 days, which equals 1560 student-days.

If 10 more students are admitted, the total number of students becomes 26 + 10 = 36 students.

To calculate how many days the provisions would last for 36 students, we divide the total provision "student-days" by the new total number of students:

1560 student-days / 36 students = 43.33 days (approximately)

Therefore, with 10 more students admitted, the provisions would be enough for approximately 43 days.

Answer:

44 days for the 36 students.

Step-by-step explanation:

Let's break down the information given:

Initially, there are 26 students in the hostel and provisions for 60 days. This means that the total "student-days" that the provisions can support is 26 students * 60 days = 1560 student-days.

Now, 10 more students are admitted to the hostel. So, the total number of students becomes 26 + 10 = 36 students.

We want to find out for how many days the provisions will be enough for these 36 students.

We can set up a proportion to solve this:

Initial student-days = New student-days

1560 student-days = 36 students * x days

Now solve for x:

x = 1560 student-days / 36 students

x = 43.33 days

Since you can't have a fraction of a day, we'll round up to the nearest whole day. Therefore, the provisions would be enough for approximately 44 days for the 36 students.

Solve the system using any method:
y = x - 3
y = 7x + 3

Answers

Answer:

x=-1, y=-4

Step-by-step explanation:

For this question, you can replace y in one equation with the second one.

This means x-3=7x+3.

From there, you subtract x from each side, giving -3=6x+3.

Subtracting 3from each side makes it -6=6x.

Dividing both sides by 6 leaves x isolated, with a result of x=-1.

You can substitute the value of x into either equation to work out y. I'm using the first one, as it has smaller numbers.

This equation is now y=-1-3, which can be solved for y=-4.

**This content involves simultaneous equations, which you may wish to revise. I'm always happy to help!