Find the slope and y intercept of the line 6x+ 2y=-88

Answers

Answer 1

Answer: 6x + 2y = -88
2y = -88 -6x
y=-88/2 -6/2x
y= -44 - 3x
y = -3x - 44

Y intercept = -44
Slope/m = -3 (aka) -3/1

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|-4k|>16 Solve inequality. Graph the solution set on a number line.

Answers

Answer (it has two solutions):

k > 4
k < -4

I hope this helps!

Eliminate the y in the following system of equations. What is the result when you add the two equations?x+y=2
3x-4y=27

A.7x=29
B.x=-23
C.7x=35
D.4x=29

Answers

Final answer:

By manipulating and then adding the given system of equations, we can eliminate the variable 'y', resulting in the equation 7x = 35.

Explanation:

To eliminate the variable y in the given system of equations, we need to manipulate the equations to cancel out the y term. The system of equations is:

x + y = 2

3x - 4y = 27

We can accomplish y-elimination by first multiplying the first equation by 4 to match the coefficient in front of y in the second equation. The equations now are:

4x + 4y = 8

3x - 4y = 27

Now, we can add the two equations together, effectively eliminating the y-variable:

4x + 3x = 8 + 27

7x = 35

Learn more about Elimination Method in System of Equations here:

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Answer:

Step-by-step explanation:

x + y = 2

Subtract x from both sides;

y = -x + 2

3x - 4y = 27

Substitute y;

3x - 4(-x + 2) = 27

Distribute;

3x + 4x - 8 = 27

7x - 8 = 27

Add 8 to both sides;

7x = 35

Divide both sides by 7;

x = 5

Question 5: CONSUMER MATH

Answers

Answer:aaaaa

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Step-by-step explanation:

Use the substitution method to solve the system of equations

3x+2y=13

y=x-1

Answers

Answer:

$x=3\ny=2$

Step-by-step explanation:

$3x+2y=13\ny=x-1$

Solve for $y=x-1$ for y:

$y=x-1$

Substitute $x-1$ for y in $3x+2y=13$ :

$3x+2y=13$

$3x+2(x-1)=13\n$

$5x-2=13$

$5x=13+2$

$5x=15$

$x=15/5$

$x=3$

Substitute 3 for x in $y=x-1$ :

$y=x-1$

$y=(3)-1$

$y=2$

$x=3$ and $y=2$

hope this helps...

I’m having a hard time understanding substitution. Please help!

Answers

$b_1=(2A)/(h)-b_2$

Step-by-step explanation:

Given expression is;

$A=(h(b_1+b_2))/(2)$

Solving for $b_1$

Multiplying both sides by 2

$2*A=(h(b_1+b_2))/(2)*2\n2A=h(b_1+b_2)$

Dividing both sides by h

$(2A)/(h)=(h(b_1+b_2))/(h)\n(2A)/(h)=b_1+b_2$

Subtracting $b_2$ from both sides

$(2A)/(h)-b_2=b_1+b_2-b_2\n(2A)/(h)-b_2=b_1\nb_1=(2A)/(h)-b_2$

$b_1=(2A)/(h)-b_2$

Keywords: division, subtraction

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A curve is described by the following parametric equations:x = 2 - t
y = x^2 + 1
Which statement best describes the curve?

The curve is a parabola with a vertex at (2, 1) and is traced from left to right for increasing values of t.
The curve is a parabola with a vertex at (2, 1) and is traced from right to left for increasing values of t.
The curve is a parabola with a vertex at (-2, -1) and is traced from left to right for increasing values of t.
The curve is a parabola with a vertex at (-2, -1) and is traced from right to left for increasing values of t.

Answers

When you use a parameter to describe equations then you are talking about Parametric Equations, that is, you can write both $x$ and $y$ as functions of a parameter $t$ . In this problem we have the following equations:

$x=2-t \n y=x^(2)+1$

So substituting $x$ in $y$ we have:

$y=(2-t)^2+1 \n y=4-4t+t^2+1 \n y=t^2-4t+5$

So this equation represents a parabola where $y$ is the dependent variable and $t$ is the independent variable. This equation is shown in the figure below, the best statement that describes this curve is:

The curve is a parabola with a vertex at (2,1) and is traced from left to right for increasing values of t.

A curve is described by parametric equations x = 2 - t;

y = x^2 + 1 statement the curve is a parabola with a vertex at (2,1) and is traced from left to right for increasing values of t is the best-described curve.

We use a parameter to describe equations then we are talking about Parametric Equations, that isWe can write both as functions of a parameter.

We have given the parametric equation

$x = 2 - t\ny = x^2 + 1$

What is the parametric equation?

The parametric equation defines a group of quantities as functions of one or more independent variables called parameters.

So substituting the value of x in y we get,

$y=(2-t)^2+1\ny=2^2-4t+t^2+1\ny=4-4t+t^2+1\ny=5-4t+t^2\n$

So this equation represents a parabola where y is the dependent variable and t is the independent variable.

This equation is shown in the following figure, the best statement that describes the curve.

Therefore we can say that the curve is a parabola with a vertex at (2,1) and is traced from left to right for increasing values of t.

To learn more about the parametric equation visit:

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