Answer:
substitution (or addition)
Step-by-step explanation:
A simple strategy for this system is to use substitution. The first equation is easily solved for x, so you could substitute that into the second equation:
x = 6y -8
7(6y -8) -y = -2 . . . . . x variable eliminated
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The second equation is easily solved for y, so you could substitute that into the first equation.
y = 7x +2
-x +6(7x +2) = 8 . . . . . y-variable eliminated
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The "addition" method is always a good way to eliminate a variable.
When the coefficient of a variable in one equation is a divisor of the coefficient of that variable in the other equation, a simple multiplication and addition will do.
To make the coefficient of x in the first equation the opposite of the coefficient of x in the second, multiply the first equation by 7. Adding that result to the second equation will eliminate x:
7(-x +6y) +(7x -y) = 7(8) +(-2)
42y -y = 56 -2 . . . . . . x-variable eliminated
Likewise, the second equation can be multiplied by 6 and added to the first to eliminate the y-variable:
(-x +6y) +6(7x -y) = (8) +6(-2)
-x +42x = -4 . . . . . . . . y-variable eliminated
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It is often the case that using either substitution or "addition" requires about the same amount of work.
Here, the solutions are (x, y) = (-4/41, 54/41).
To eliminate a variable in the given system of equations, you can use the elimination method. By multiplying the equations by suitable numbers and adding them, you can cancel out one of the variables, simplifying the process to solve for the other variable.
You can eliminate a variable in the given system of equations: −x+6y=8 and 7x-y=−2 by using either the substitution method or the elimination method. For this scenario, the elimination method will work best.
Strategy:
This variable eliminationstrategy lets you solve one equation for one variable, simplifying the process of finding solutions for a system of equations.
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A point is a location and a line has many points located on it.
A line and a point cannot lie on the same plane.
A line and a point cannot be collinear.
2. Trisha drew a pair of line segments starting from a vertex.
Which of these statements best compares the pair of line segments with the vertex?
The line segments and the vertex have length as a dimension of measurement and there are three collinear points on each.
Line segments and the vertex have two endpoints each and the distance between the end points is their dimension.
Line segments have two endpoints and a vertex is a common endpoint where two line segments meet.
The line segments and the vertex have their lines extending in one direction only and the lengths of both are infinite.
Answer:
x= 7/3 (fraction)
Step-by-step explanation:
If you plug it in it will work
b) x = 6, y = 11
c) x = 8, y = 10
d) x = -10, y = 7