Which of the following is the correct factored form of the given equation?4x^2 0 25 = 0
(4x 0 5)(x + 5) = 0
(2x 0 5)(2x + 5) = 0
2(x 0 5)² = 0

Answers

Answer 1

Answer: number 2 is the correct one

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HELP PLSS WHICH ONE IS IT!!Question 7 (3.03): Use the graph representing bacteria decay to estimatethe domain of the function and solve for the average rate of change across
the domain.

Answers

Answer:The domain of a function is the set of input values of the function.

The domain of the function is: [0,18]

The average rate of change across the domain is -3.33

Step-by-step explanation:From the graph, we have the following highlights.

The graph starts from the origin

The graph ends at x = 18

So, the domain of the function is: [0,18]

The average rate of change is calculated as:

From the graph, we have:

So, we have:

This gives

Hence, the average rate of change across the domain is -3.33

Read more about exponential functions at:

brainly.com/question/18719551

The trees at a national park have been increasing in numbers. There were 1,000 trees in the first year that the park started tracking them. Since then, there have been as many new trees each year. Create the sigma notation showing the infinite growth of the trees and find the sum, if possible. Year New trees 1 1000 2 200 3 40

Answers

Answer:

Step-by-step explanation:

There were 1000 trees in the first year and every year new trees are getting added.

The sequence formed for the new trees every year is

Year 1 2 3

New trees 1000 200 40

We see a geometric sequence has been formed by the new trees added

Ratio of the second year and 1st year trees added = $(200)/(1000)=(1)/(5)$

Similarly ratio of trees added in 3rd year to 2nd year = $(40)/(200)=(1)/(5)$

So there is a common ratio of $(1)/(5)$

Explicit formula of a geometric sequence representing growth of the trees by

$T_(n)=a(r)^(n-1)$

where a = number of trees grown first year

r = common ratio

n = number of years

Explicit formula showing the growth of the trees using sigma notation will be

$\sum_(n=1)^(\infty)1000((1)/(5))^(n-1)$

And Formula for number of trees every year will be

$\sum_(n=1)^(\infty)1000+1000((1)/(5))^(n-1)$

$\sum_(n=1)^(\infty)1000[1+((1)/(5))^(n-1)]$

Sum of the trees will be

$S=(a)/(1-r)$

= $(2000)/(1-(1)/(5))$

= $(2000)/((4)/(5) )$

= $(2000* 5)/(4)$

= 2500

813,763 round to the nearest ten thousand

Answers

answer:

To round 813,763 to the nearest ten thousand, we look at the digit in the ten thousand place. In this case, the digit in the ten thousand place is 3.

If the digit in the ten thousand place is 0, 1, 2, 3, or 4, we round down to the nearest ten thousand. Since 3 is in the range of 0 to 4, we round down.

To round down, we keep the digits to the right of the ten thousand place as 0. Therefore, when we round 813,763 to the nearest ten thousand, the answer is 810,000.

So, 813,763 rounded to the nearest ten thousand is 810,000.

Alli <3

a local business was looking to hire a landscaper to work on their property. they narrowed their choices to two companies. flourish landscaping company charges a flat rate of $120 per hour. green thumb landscapers charge $70 per hour plus a $1600 equipment fee. write a system of equations representing how much each company chargers. determine and state the number of hours that must be worked for the cost of each company to be the same. if it is estimated to take at least 35 hours to complete the job, which company will be less expensive? justify your answer

Answers

Flourish- 120x
Green Thumb- (70x)=1600

Flourish- 120*35= $4200
Green Thumb- (70*35)+1600= $4050

It would be less expensive to hire Green Thumb Landscapers. There is a $150 difference between the two

It would take 32 hours of work for the cost to be the same for both companies

7.7z-2=6.7z-2 the solution is