Two of the three sides of a triangle are 20 and 15. Which of the following numbers is not a possible perimeter of the triangle?a. 52
b. 57
c. 62
d. 67 e.72

Answers

Answer 1
Answer: Given:
1st side = 15
2nd side = 20
3rd side = ?

We will use a triangle inequality where the 3rd side is greater than the difference of the two sides and less than the sum of the two sides.

20 - 15 < x < 20 + 15
5 < x < 35

If x = 5 ; then the perimeter would be 5 + 15 + 20 = 40
if x = 35, then the perimeter would be 35 + 15 + 20 = 70

So the perimeter is within the range of 40 and 70.

Among the choices, E. 72 is outside the range. Therefore, it is not a possible perimeter of the triangle.

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Answers

Do u have a picture of the assignment?

Enter the plan width for the rectangular room. Round your answer to the nearest tenth.plan length:
4 in.
actual width:
18 ft
actual length: 16 ft


The plan width is
in.

Answers

Answer:

4.5 inches

Step-by-step explanation:

Given: plan length = 4 inches, actual width = 18 feet, actual length = 16 feet

To find: plan width

Solution:

1 feet = 12 inches

Plan length = 4 inches

Actual width = 18 feet= 18× 12 = 216 inches

Actual length = 16 feet = 16× 12 = 192 inches  

Plan length/plan width  =  actual length/actual width

(4)/(plan\,\,width)=(192)/(216)\n  plan\,\,width=(216)/(192)(4)=4.5\,\,inches

Read the picture above to answer. Thanks

Answers

The answer and explanation is down below. HTH

ProblemThe formula for the remaining volume of fuel in a car's tank is I-E\cdot DI−E⋅DI, minus, E, dot, D, where III is the initial volume of fuel, EEE is the fuel efficiency, and DDD is the distance traveled.

Carson drove a distance of 120120120 kilometers. He initially had 303030 liters of fuel, and his car's fuel efficiency is 100100100 cubic centimeters per kilometer.

What calculation will give us the estimated volume of fuel that remains in Carson's tank by the end of the drive, in liters?

Answers

Answer:

18 litres

Step-by-step explanation:

The formula for the remaining volume of fuel in a car's tank is expressed as;

V = I - E.D

where;

I is the initial volume of fuel,

E is the fuel efficiency, and;

D is the distance traveled.

Given

I = 30 litres

1m³ = 1000L

x = 30L

x = 30/1000

x = 0.03m³

I = 0.03m³

E = 100cm³/km

E = 100*10^-6m³/km

E = 10^-4m³/km

E = 10^-4m³/1000m

E = 10^-7m²

D = 120km

Convert km to metres

D = 120km = 120,000m

Substitute the results into the formula;

V = I - E.D

V = 0.03 - (10^-7)(120,000)

V = 0.03 - 0.012

V= 0.018 m³

Convert 0.018 m³ to litres

Since 1 m³ = 1000L

0.018 m³ = y

cross multiply;

y  = 1000 * 0.018

y = 18 litres

Hence volume of fuel that remains in Carson's tank by the end of the drive is 18 litres

What is the answer to 2/3[(15-6)-8(8+1)]

Answers

Calculate the brackets:
(2)/(3)[ 9- 8 *9] =   (2)/(3) (9-72) =  (2)/(3) (-63) = 2*(-21) = \boxed {-42} <--answer

What is the volume of a sphere with the radius of 2 cm?

Answers

V=43πr3=43·π·
333.51032 =33.51 is the answer
Short Answer: 33.5cm3. 

Longer Answer: The formula for volume of a sphere is ( 4 * pi * radius^3) / 3. So, when the radius is 2cm, then it would be ( 4 * 3.14 * 2^3) / 3. We have to do the exponents first, so 2 ^ 3 is 2 * 2 * 2 = 8. Then, we solve the rest of the expressions within the bracket, which will give us ( 100.48 ) / 3, and that equals 33.5