The human resources manager at a company records the length, in hours, of one shift at work, X. He creates the probability distribution below. What is the probability that a worker chosen at random works at least 8 hours?

Answers

Answer 1

Answer: The words at least means that the worker needs to work 8, 9 or 10 hours. We can add probabilities, so we will add .6 (for those working 8 hours), .15 (for those working 9 hours) and .08 (for those working 10 hours) to get a total probability of .83.

Answer 2

Answer:

Answer:

.84 would be the answer

Step-by-step explanation:

because I got it correct on my test.

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The coefficient of 6x is ___. A.) 1 B.) 6 C.) x
Which amount is largest? 100 g 1 kg 1,000 mg 1 dg
1) point R has coordinates of (1,0) point S is symmetric to point R with respect to the line y=-2, what are the coordinates of point S2)point N has coordinates of (-1,2) point M is symmetric to point N with respect to the line y=X, what are the coordinates of point M 3) x^2=36 A. 9sqrt. 2 - 9sqrt. 2 B. 6 - 6 C. 4sqrt. 3 - 4sqrt. 3 D. 18 - 18 4) x^2=90 A. 10 sqrt. 3 - 10 sqrt. 3 B. 3 sqrt. 10 -3 sqrt. 10 C. 3 sqrt. 15- 3 sqrt. 15 D. 45 - 45
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In a video game, two golfers tee off at hole 6, which has the coordinates (–32, –27). Golfer A’s ball lands at (–43, –18). Golfer B’s ball lands at (–44, –16). Which golfer hit the longer shot?

Answers

Answer:

Golfer B's hit the longer shot.

Step-by-step explanation:

In a video game, two golfers tee off at hole 6

Position of hole at (-32,-27)

Golfer A's ball lands at (-43,-18)

Golfer B's balls lands at (-44,-16)

Distance formula:

$d=√((x_2-x_1)^2+(y_2-y_1)^2)$

Distance of shot of Golfer A's $=√((-32+43)^2+(-27+18)^2)=√(11^2+9^2)\approx 14.21$

Distance of shot of Golfer B's $=√((-32+44)^2+(-27+16)^2)=√(12^2+11^2)\approx 16.28$

16.28 > 14.21

Golfer B's shot > Golfer A's shot

Hence, Golfer B's hit the longer shot.

Using Pythagoras' theorem, you can work out the distance the balls travelled.
Golfer A: -43 - -32 = -43 + 32 = -11
-27 - -16 = -27 + 16 = -11
a² + b² = c²
(-11)² + (-11)² = √242 = 15.556

Golfer B: -44 - -32 = -44 + 32 = -12
-27 - -16 = -27 + 16 = -11
a² + b² = c²
(-11)² + (-12)² = √265 = 16.278

∴ B hit the longest shot.

MDM4U11. Avery and Bradley work at a large electronics manufacturer that produces DVD players. The
defective rate on the assembly line has gone up to 12% and the manager wants to know the
probability that a skid of 50 DVD players will contain at least 3 defective units.
a) Help Avery use the binomial distribution P(x)=, C.pqrs to answer this question

Answers

Answer:

0.9487

Step-by-step explanation:

a) The probability of having a defective product = p = 12% = 0.12

The probability of not having a defective product = q = 1 - p = 1 - 0.12 = 0.88

The number of DVD players = n = 50

X is the number of defective products.

The probability that a skid of 50 DVD players will contain at least 3 defective units = P(X ≥ 3) = 1 - P(X ≤ 2)

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

Using binomial:

P(X = 0) = $C(n,x)p^xq^(n-x)=C(50,0)p^0q^(50-0)=(50!)/((50-0)!0!)*0.12^0*0.88^(50-0)=0.0017$

P(X = 1) = $C(n,x)p^xq^(n-x)=C(50,1)p^1q^(50-1)=(50!)/((50-1)!1!)*0.12^1*0.88^(50-1)=0.0114$

P(X = 2) = $C(n,x)p^xq^(n-x)=C(50,2)p^2q^(50-2)=(50!)/((50-2)!2!)*0.12^2*0.88^(50-2)=0.0382$

P(X ≤ 2)= 0.0017 + 0.0114 + 0.0382 = 0.0513

P(X ≥ 3) = 1 - P(X ≤ 2) = 1 - 0.0513 = 0.9487 = 94.87%

The function f(x)=600+2x over x yields the average cost in dollars for a company to produce x calendars. Which statement best fits the situation modeled by the function? a) The company spends $600 on a new computer and printer before beginning the project.
b) The company takes 600 photos before selecting which ones to use for its calendars.
c) The company expects to sell 600 calendars each month.
d) The company will sell the calendars for $6.00 each.

Answers

Answer:

The correct option is a.

Step-by-step explanation:

The average cost function is

$f(x)=(600+2x)/(x)$

Where x is the number of calendars produced.

The average cost formula is

$AC=\frac{\text{Total Cost}}{\text{Number of items}}$

Therefore the total cost is defined b the function

$g(x)=600+2x$

Here 600 is the initial cost and the cost each unit is 2.

Initial cost is the fixed cost which occurs at zero level of productivity.

The company spends $600 on a new computer and printer before beginning the project. The option (a) is correct.

The function f(x)=600+2x over x yields the average cost in dollars for a company to produce x calendars. The statement best fits the situation modeled by the function "The company spends $600 on a new computer and printer before beginning the project.". The answer is letter A.

2. Rename .709 as a percent. a. 709% b. 70.9% * c. 79% d. 7.09% 4. Alice plays basketball. In one game she shoots 21 free throws and makes 81.25% of them. Estimate how many free throws she makes.a. about 16 b. about 2 c. about 20 d. about 14 5. Estimate 48% of $20.00. a. about $12.00 b. about $11.00 c. about $15.00 d. about $10.00 * 6. The bill at a restaurant is $100, and Mrs. Johnson wants to leave a 15% tip. Approximately how much money should she leave?
a. about $5.00 b. about $10.00 c. about $15.00 * d. about $20.00 7. Which proportion can be used to solve the following percent problem? What is 50% of 70?
8. What percent of 50 is 15? a. 4% b. 25% c. 30% d. 15% 9. 30% of 60 is what number? a. 15 b. 30 c. 18 * d. 40 The choices with * is what I think the answer is please check them, and help me the others.

Answers

2) Your answer is correct. It is B. 70.9%
4) We can round 81.25% to 80 and 21 shots to 20. 20 x 0.8 = 16.
The answer is A. about 16
5) Your answer is correct. 48% is almost half; half of $20 is $10, so the answer is D.
6) Your answer is correct, C. 15% x 100 = $15
7) The proportion 50/100 = x/70 can help solve this. The answer will be 35.
8) We simply do:
15/50 x 100 = 3/10 x 100 = 30%
9) You are correct, C. 0.3 x 60 = 18

Approximate the value of 44 to the nearest hundredth

Answers

I dont really understand the question. But from how u asked it then it would be 44.00

Ms. Soar flew 220 mi in 1.6 h. She then landed at the Aspen Airport to visit a friend. In the second portion of her trip, Ms. Soar flew 312 mi, which took 2.2 h.What was her plane’s average speed for the entire trip?

Answers

220 mi+312 mi= 532 mi