Can a Right Triangle be a(n)
A.Obtuse
B.Scalene

Answers

Answer 1
Answer: Your answer is B hope i helped
Answer 2
Answer: A scalene because an obtuse is more than 90 degrees

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derivative of this function Y= -7X³ -8X² +6X +3

Express on simplest form in terms of i: sqrt-16

Answers

√(-16)=√(-1\cdot16)=√(-1)\cdot√(16)=i\cdot4=4i

One person can do a certain job in twenty-one minutes, and another person can do the same job in twenty-eight minutes. How many minutes will it take them to do the job together?6 min
12 min
24 min

Answers

The number of minutes that it will take for them to do the job together is:

  • 12 minutes

What is the formula for work done together?

To arrive at the correct answer, it is necessary to factor in the number of minutes worked by each individual. For that, we can assign them х and у.

So the number of hours worked by the person х is 21 minutes

and the number of hours worked by person у is 28 minutes

When they work together, they will spend:

XY minutes / X+ Y minutes

21 min * 28 min = 588 minutes\n\n21 min + 28 min = 49 minutes

Therefore;

588 / 49 = 12 minutes.

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(1)/(21)+(1)/(28)=(1)/(x)\n(4)/(84)+(3)/(84)=(1)/(x)\n(7)/(84)=(1)/(x)\n7x=84\nx=12

You are choosing between two health clubs. Club A offers membership for a fee of $ 14 $14 plus a monthly fee of $ 15. $15.  Club B offers membership for a fee of $ 18 $18 plus a monthly fee of $ 14. $14.  After how many months will the total cost of each health club be the​ same? What will be the total cost for each​ club?

Answers

Answer:

After 4 months total cost of each health club would be the​ same that is $74.

Step-by-step explanation:

Let x represent number of months.

We have been given that Club A offers membership for a fee of $14 plus a monthly fee of $15.

The total cost of using Club A for x months would be 15x+14.

We have been given that Club B offers membership for a fee of $18 plus a monthly fee of $14.

The total cost of using Club B for x months would be 14x+18.

Let us equate both equations to find number of months, when both health clubs cost would be same.

15x+14=14x+18

15x-14x+14=14x-14x+18

x+14=18

x+14-14=18-14

x=4

Therefore, after 4 months the total cost of each health club would be the​ same.

The total cost of using Club A: 15(4)+14=60+14=74

The total cost of using Club B: 14(4)+18=56+18=74

Therefore, the total cost for each club would be $74.

Do you know how to do 5/3x 1/6 - 1

Answers

To do this multiply the top and bottom numbers together in the fraction. Which will be 5/18. Then convert 1/1 to a fraction that has the same denominator as our previous answer. To carry out the subtraction. 5/18-18/18= -13/18. This is in lowest terms

ANSWER ASAP PLEASE! What is the equation of a parabola in standard form given the directrix is y = 3 and the focus is (3,-3)?(x - _ )^2 = _y

Answers

Answer: (x - 3)^2 = -24(y + 3)

Step-by-step explanation:

To find the equation of the parabola in standard form, we can use the formula (x - h)^2 = 4p(y - k), where (h, k) is the vertex and p is the distance between the vertex and the focus.

Given that the directrix is y = 3 and the focus is (3, -3), we can see that the parabola opens downward.

The focus is (h, k + p) = (3, -3) and the directrix is y = k - p = 3. By comparing the y-coordinates, we can find p.

-3 = 3 + p

p = -6

Substituting the values into the formula, we get:

(x - 3)^2 = 4(-6)(y - (-3))

So, the equation of the parabola in standard form is (x - 3)^2 = -24(y + 3).

What are the domain, range, and asymptote of h(x) = 6x – 4?

Answers

The domain is x = 1, 2, 3, 4, 5...... ∈ R (set of real number).

Range:  (0,∞)

Asymptote: y=0.

What is Domain, Range and Asymptote?

The range of a function is the set of output values for the dependent variable.

The range, however, is bounded by the horizontal asymptote of the graph of f(x).

A straightline that continuously approaches a certain curve without ever meeting it is an asymptote.

Given:

h(x) = 6x – 4

Now, the domain is the input value as

x = 1, 2, 3, 4, 5...... ∈ R (set of real number)

So, h(1) = 6-4 =2

and, h(2) = 12-4 = 8

and, the range is (0,∞)

Now, the asymptote h(x)= 0

6x-4 = 0

x= 2/3.

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h(x)=6x−4  or  h(x)=6x−4 
If the former, the domain is all real numbers, often denoted by the symbol R
the range is (0,∞) 
asymptote is y = 0