To find the length and width of the wall of the barn, set up an equation using the given information. Solve the equation by factoring, and find the values of x and x + 12, which will be the width and length of the wall, respectively. The width of the wall is 6 feet, and the length is 18 feet.
To find the length and width of the wall of the barn, we can use algebra. Let's say the width of the wall is x. According to the problem, the length is 12 feet longer than the width, so the length is x + 12.
The area of a rectangle is found by multiplying the length by the width, so we can set up the equation
x(x + 12) = 108.
Solving this equation will give us the values of x and x + 12, which will be the width and length of the wall, respectively.
The equation is x(x + 12) = 108.
Expanding the equation gives x^2 + 12x = 108.
Rearranging the equation to bring everything to one side gives
x^2 + 12x - 108 = 0.
Factoring the quadratic equation gives (x + 18)(x - 6) = 0.
Setting each factor equal to zero gives x = -18 or x = 6.
Since we can't have a negative width, the width of the wall is 6 feet.
Therefore, the length of the wall is x + 12 = 6 + 12 = 18 feet.
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b) 60°, 60°, and 60°
c) 45°, 45°, and 90°
d) None of these.
a²-25 8a
The slope intercept form which is y = mx+ c, of the given line is,
y = (1/2)x - 3/2
The best approach to determine without using any geometrical tools if the lines are parallel, perpendicular, or at any angle is to measure the slope.
The slope-intercept form of a line is:
y = mx + c
Where,
m represents the slope of the line
c represents the y-intercept of the line
The given equation of a line is:
x-2y=3
Subtract x both sides,
-2y = -x + 3
Divide both sides of the equation by -2,
y = (1/2)x - 3/2
This is of the form y = mx + c
Slope: m = 1/2
Y-intercept: c = -3/2
Hence,
The slope intercept of the line is y = (1/2)x - 3/2.
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