The dimensions of a large room are double the dimensions of a small room.Both rooms are rectangular prisms. The volume of the small room is 10 cubic
metres.
What is the volume of the large room?

Answers

Answer 1
Answer: The volume would be 80 cubic metres. Think about the three different dimensions for the small room as x,y and z. Therefore the volume is x*y*z= xyz. Now for the bigger room, the dimensions would be 2x,2y and 2z. Therefore, its volume would be 2x*2y*2z= 8xyz. Since xyz (volume of the smaller room)= 10 cubic metres, the bigger room's volume will be 8*10= 80 cubic metres.

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What is the image of (-2, -5) after a reflection over the line y = x

Answers

Answer:

(-5, -2)

Step-by-step explanation:

Rule for reflection over y = x :

(x, y) -> (y, x)

Answer:

2, -5

Step-by-step explanation:

What is the domain and range of f(x)=35x​

Answers

Answer:

Domain and Range are all real number

Step-by-step explanation:

Answer is above

WILL CHOOSE BRAINLIEST! PLEASE HELP! 15 POINTS!Find the area of the shaded segment of the circle.

Answers

[(81*3.14)/4] - (81/2)

Answer:

The shaded segment  = The arc area - The triangle

The arc area = pi x radius^2 x angle/360

                     = pi x 9^2 x (360-270)/360 = 63.61 (m2)

The triangle area = 9 x 9/2 = 41.5 (m2)

(because this is right triangle)

=> The shaded segment = 63.61 - 41.5 = 22.11 (m2)

What is the range of each function given below?
a. Let f(x) = 9x − 1.

Answers

Answer:

Range of f=R

Step-by-step explanation:

We are given that a function

f(x)=9x-1

We have to find the range of given function.

The given function is linear function because the degree of function is 1.

When the degree of function is 1 then the function is called the linear function.

The domain of linear function is a set  of real numbers because it can be defined for all real values of x.

Domain of given function =R

When we substitute the real value of x  in given function then we get a  real number also.

Therefore, the range of f=R

1. Simplify (4xy^2)^3(xy)^5 . 2. Simplify (2t^–3)^3(0.4r)^2

Answers

I hope this helps you

A software designer is mapping the streets for a new racing game. All of the streets are depicted as either perpendicular or parallel lines. The equation of the lane passing through A and B is -7x + 3y = -21.5. What is the equation of the central street PQ?See attachment below for picture/answer choices

Answers

Answer:

-1.5x-3.5y=-31.5

Step-by-step explanation:

we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

m1*m2=-1

In this problem line AB and line PQ are perpendicular

Step 1

Find the slope of the line AB

The equation of the line AB is

-7x+3y=-21.5

isolate the variable y

3y=7x-21.5 ------> y=(7/3)x-21.5/3

The slope of the line AB is equal to

m1=7/3

Step 2

Find the slope of the line PQ

remember that

m1*m2=-1

we have

m1=7/3 ----> slope line AB

so

substitute and solve for m2

(7/3)*m2=-1

m2=-3/7

Step 3

Find the equation of the line PQ

The equation of the line into point-slope form is equal to

y-y1=m(x-x1)

we have

m=-3/7

P(7,6)

substitute

y-6=(-3/7)(x-7)

y=(-3/7)x+3+6

y=(-3/7)x+9 -----> multiply by 7 both sides

7y=-3x+63

7y+3x=63 -----> divide by 2 both sides

1.5x+3.5y=31.5 -----> multiply by -1 both sides

-1.5x-3.5y=-31.5

its B -1.5x − 3.5y = -31.5