Why when I sum the angles I don't get 180

Answers

Answer 1

Answer: You don't have all the numbers, you don't know what X equals, you need to know what X equals in order to complete the equation

Answer 2

Answer: 5x+20+7x-80=180
12x-60=180
x=20
I think that's the answer

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You drive 6.0 km at 50 km/h and then another 6.0 km at 90 km/h. Your average speed over the 12 km drive will be _________

Answers

Answer:

$64.29\ (km)/(h)$

Step-by-step explanation:

hello

the speed is the relation between a distance traveled and the time used for it and it is given by the equation

$v =(displacement)/(time)\n (1)v=(d)/(t)$

Now, the average speed will be

$v_(average) =(displacement\ total)/(total\ time)\n (1)v=(d)/(t) \n(2)v_(average)=(d_(t) )/(t_(t) )$

Step 1

I drive 6.0 km at 50 km/h

from (1) it is possible to isolate t

$(1)v=(d)/(t)\nt=(d)/(v)$

Let

$v=50 (km)/(h) \nd=6.0 km\nt=(d)/(v) \nt=(6.0 km)/(50 (km)/(h))\nt_(1)=0.12\ hours\n$

Step 2

then I drive 6.0 km at 90 km/h

$v=90 (km)/(h) \nd=6.0 km\nt=(d)/(v) \nt=(6.0 km)/(90 (km)/(h))\nt_(2)=0.067\ hours\n$

Step 3

FInd total time and total displacement

$Total\ time=t_(1) +t_(2) \nt_(t) =0.12\ hours +0.067\ hours =0.187\ hours\n\ntotal\ distance\ =d_(1) +d_(2)=6.0\ km +6.0\ km= 12\ km\n$

step 4

finally, put these values into the equation(2)

$v_(average)=(d_(t) )/(t_(t) )\nv_(average)=(12\ km )/(0.187\ h )\nv_(average)=64.29\ (km)/(h)$

V=64.29 km/h

Have a good day

Answer:

64.2857 km/h

Step-by-step explanation:

Time taken to drive the first 6.0 km in hours = 6/50

Time take to drive another 6.0 km in hours = 6/90

Total time taken to drive 12 km in hours = (6/50) + (6/90)

= 6(50+90)/50x90

= 6x140/50x90

= 840/4500

The average speed over the 12 km is therefore 12 divided by 840/4500

= (12 x4500)/840

= 64.2857 km/h

A game has a rectangular board with an area of 44 in2. There is a square hole near the top of the game board in which you must not toss in a bean bag. The square has side lengths of 3 in. What is the probability of not tossing the bag through the hole?A)9/44
B)3/9
C)3/44
D)35/44

Answers

A. 9/44 idk if it is the right anwser but good
Luck

To get from the post office to the library, Sindy walked due north and then due east. The distance Sindy walked east is 20 meters more than the distance she walked north. If Sindy were able to walk directly from the post office to the library in a straight line, she would have walked 150 meters. Suppose x represents the distance Sindy walked north. Which equation can be used to find x?x^2 (x 20)^2=150^2
202=x^2-150^2
x (x 20)=150
x^2 (x 150)^2=20^2

Answers

Answer:

x² + (x + 20)² = 150²

Step-by-step explanation:

Sindy walked x meters in north and then x+20 meters toward east. If Sindy were able to walk directly from the post office to the library directly in a straight line, the distance she would have walked 150 meters.

Thus Sindy forms a right angle triangle as in the figure attached.

From Pythagoras theorem

x² + (x + 20)² = 150²

This is the equation we can use to find x.

Technically, none of the equations.

The equation you're looking for would be:

x²+(x+20)²=150²

Kenya has 2 hours to make a 104 mile road trip. What rate must she average to make the trip in 2 hours?51 mph

52 mph

53 mph

54 mph

Answers

104/2 = 52
answer is 52 mph
hope it helps

Find the coordinates of point X that lies along the directed line segment from Y(-8, 8) to T(-15, -13) and partitions the segment in the ratio of 5:2. A. (-5, -15) B. (-23, -5) C. (-13, -7) D. (-11.5, -2.5)

Answers

Answer:

C. (-13, -7)

Step-by-step explanation:

The location of a point O(x, y) that divides a line AB with location A $(x_1,y_1)$ and B $(x_2,y_2)$ in the ratio m:n is given by:

$x=(m)/(m+n) (x_2-x_1)+x_1\n\ny=(m)/(m+n) (y_2-y_1)+y_1$

Therefore the coordinates of point X That divides line segment from Y(-8, 8) to T(-15, -13) in the ratio 5:2 is:

$x=(5)/(5+2) (-15-(-8))+(-8)\n\nx=(5)/(7) (-15+8)-8=(5)/(7)(-7)-8=-5-8=-13 \n\n\ny=(5)/(5+2) (-13-8)+8\n\ny=(5)/(7) (-21)+8=5(-3)+8=-15+8=-7$

Therefore the coordinates of point X is at (-13, -7)

Hi, can anyone graph y=15x+75?

Answers

Answer:

Graph

Step-by-step explanation:

The simplest way to graph a linear equation is to make an x, y chart.

Plug in values for x ( 3 values for x works ), then find the y values and graph the cordinates.

Another way to graph the above line is to identify the slope and the y-intercept. Because the function is in slope-intercept form, we can readily see both ( slope intercept form is y= mx + b where m= slope and b= y-intercept )! So b= 75 and m= 15. So to graph the y-intercept, it is ( 0, b ) and just count the slope from that point!

Final answer:

To graph the equation y = 15x + 75, start by plotting the y-intercept (0,75). Then move 15 units up and 1 to the right from the intercept. Connect the points to create the graph.

Explanation:

To graph the equation y = 15x + 75, you need to recognize it as the linear equation in slope-intercept form, y = mx + b. In this equation, m (slope) is 15 and b (y-intercept) is 75.

Start by plotting the y-intercept which is at the point (0, 75) on the y-axis. Then, from that initial point, use the slope or 'rise over run,' to find the next points. Given the slope is 15 (or 15/1), you will go up 15 units and right 1 unit from the intercept to plot your next point. Continue this process until you have enough points to produce a straight line.

By connecting these plotted points, you create the graph of y = 15x + 75.

Learn more about Graphing Linear Equations

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