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Which of the following combinations represents an element with a net charge of +1 with a mass number of 75?a) 35 (o), 35 (+), 34 (-)b) 40 (o), 40 (+), 39 (-)c) 40 (o), 35 (+), 34 (-)d) 37 (o), 38 (+), 34 (-)e) 40 (o), 35 (+), 35 (-)

Answers

Answer 1

Answer:

Answer:

c) 40 (o), 35 (+), 34 (-)

Explanation:

Let us represent the element with P

Given information about the element:

Charge on P = +1

Mass number of P = 75

We can express the atom as ⁴⁵P¹⁺

The positive charge on the atom denotes that the atom has lost an electron. Electrons are negatively charge elementary particles in an atom. Therefore, the number of protons, positively charged particles are now more. This charge imbalance is what leaves atom P with a charge of +1. The difference between the proton number and number of electrons is just 1 and it represents a loss of an electron. Atoms that are not charged have their proton and electron number to be the same. Those that are negatively charge signifies that an electron has been gained and the number of electrons are greater than those of the protons.

The mass number 75 is the number of protons plus neutrons.

Option C gives the following information:

Neutron = 40

Protons = 35

Electrons = 34

Here Protons > Electrons with a difference of 1+.

Mass number = Protons + Neutrons =35 + 40 = 75

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Answers

the answer is liquid ! hope this helped :)

Challenge question! One of the things hedoesn't mention is in order to use E=hf,
and any derivation of it, the energy must
be in JOULES. We have the energy in eV.
So this will be a two step question. First,
convert the energy to joules (or use the
number from our equation sheet) then
find the wavelength. Once you are done
with that, pick the correct answer below.
8.29x10^-16 m
3.75x10^26 m
2.48x10^-7 m
3.98x10^-26 m

Answers

bro this is too hard man can do just quit

Answer:

Explanation:

Indicate the number of protons, neutrons, and electrons in each of the following species: 15N7, 33S16, 63Cu29, 84Sr38, 130Ba56, 186W74, 202Hg80

Answers

The number of protons neutrons, and electrons in each of the following species given are below;

What is the atomic number?

The total number of protons present in an atom is known as the atomic number of that atom. The atomic number has no correlation either with the number of neutrons or the number of electrons present inside an atom.

15N7 ⇒ 7 electrons, 8 neutrons, 7 protons

33S16 ⇒ 16 protons, 16 electrons, 17 neutrons

63Cu29 ⇒ 29 electrons, 34 neutrons,29 protons

84Sr38 ⇒ 38 electrons, 46 neutrons,38 protons

130Ba56 ⇒ 56 electrons, 74 neutrons,56 protons

186W74⇒ 74 electrons, 112 neutrons,74 protons

202Hg80 ⇒ 80 electrons, 122 neutrons ,80 protons

To learn more about the atomic number from here, refer to the link ;

brainly.com/question/14190064

#SPJ2

Answer:

1. 7 protons, 7 electrons, 8 neutrons

2. 16 protons, 16 electrons, 17 neutrons

3. 29 protons, 29 electrons, 34 neutrons

4. 38 protons, 38 electrons, 46 neutrons

5. 56 protons, 56 electrons, 74 neutrons

6. 74 protons, 74 electrons, 112 neutrons

7. 80 protons, 80 electrons, 122 neutrons

Most wine is prepared by the fermentation of the glucose in grape juice by yeast: C6H12O6(aq) --> 2C2H5OH(aq) + 2CO2(g) How many grams of glucose should there be in grape juice to produce 725 mLs of wine that is 11.0% ethyl alcohol, C2H5OH (d=0.789 g/cm3), by volume?

Answers

Answer:

123.41 g

Explanation:

Given that the ethyl alcohol produced is 11.0 % by volume.

It means that 1000 mL contains 110 mL of ethyl alcohol

Given that the volume is:- 725 mL

So,

Volume of ethyl alcohol = $(110)/(1000)* 725\ mL$ = 79.75 mL

Given that:- Density = 0.789 g/cm³ = 0.789 g/mL

So, Mass = Density*Volume = $0.789* 79.75\ g$ = 62.92 g

Calculation of the moles of ethyl alcohol as:-

Molar mass of ethyl alcohol = 46.07 g/mol

The formula for the calculation of moles is shown below:

$moles = (Mass\ taken)/(Molar\ mass)$

Thus,

$Moles= (62.92\ g)/(46.07\ g/mol)$

$Moles=1.37\ mol$

According to the reaction:-

$C_6H_(12)O_6_((aq))\rightarrow 2C_2H_5OH_((aq)) +2CO_2_((g))$

2 moles of ethyl alcohol is produced when 1 mole of glucose reacts

Also,

1.37 moles of ethyl alcohol is produced when $(1)/(2)* 1.37$ mole of glucose reacts

Moles of glucose = 0.685 Moles

Molar mass of glucose = 180.156 g/mol

Mass = Moles*Molar mass = $0.685* 180.156\ g$ = 123.41 g

Notice that "SO4" appears in two different places in this chemical equation. SO42− is a polyatomic ion called "sulfate." What number should be placed in front of CaSO4 to give the same total number of sulfate ions on each side of the equation? ?CaSO4+AlCl3→CaCl2+Al2(SO4)3

Answers

The number which should be placed in front of CaSO4 to give the same total number of sulfate ions on each side of the equation is; 3.

According to the question;

We are required to determine what number should be placed in front of CaSO4 to give the same number of each side of the equation.

The equation given is;

?CaSO4 + AlCl3 → CaCl2 + Al2(SO4)3

There are 3 moles of SO4 on the right hand side of the equation and as such, there should be the same number of SO4 on the left too.

In essence, the number that should be added in front of CaSO4 is; 3.

brainly.com/question/12742345

Answer : The number placed in front of $CuSO_4$ should be, three (3).

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given unbalanced chemical reaction is,

$CaSO_4+AlCl_3\rightarrow CaCl_2+Al_2(SO_4)_3$

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of chloride and sulfate ion are not balanced.

In order to balanced the chemical reaction, the coefficient 3 is put before the $CuSO_4$ , the coefficient 2 is put before the $AlCl_3$ and the coefficient 3 is put before the $CaCl_2$ .

Thus, the balanced chemical reaction will be,

$3CaSO_4+2AlCl_3\rightarrow 3CaCl_2+Al_2(SO_4)_3$

Therefore, the number placed in front of $CuSO_4$ should be, three (3).

Write the balanced equation for the equilibrium reaction for the dissociation ofsilver chloride in water, and write the K expression for this reaction. Then create an ICE chart. Since we know the equilibrium concentration of the silver ion, we can solve for Ksp.Does it agree with the literature value

Answers

Answer:

See explanation

Explanation:

Hello there!

In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

$AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)$