MATHEMATICS HIGH SCHOOL

Walter is 43 years old his daughter Paulette is 7. In how many years will Paulette be one-third of Walters age

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Answer 1
Answer: The answer is 14 when rounded to the nearest whole number, to get this you simply must divide 43 by 3 which equals to 14.333. 

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Alicia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space, as shown below:(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
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Based on the sample space, what is the probability of getting a total of 7?

4 over 36
5 over 36
6 over 36
8 over 36

Answers

i think the answer is 8/36 but i am not sure

The common stock of air united had annual returns of 13.7 percent, 4.8 percent, -6.7 percent, and 27.9 percent over the last four years, respectively. what is the standard deviation of these returns?

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JDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPE

Please help me with this

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A- 34

The angels are equal

Which one of the following examples represents a proper fraction?

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B. because its not an improper fraction and a proper fraction is the numerator is less than the denominator 
The answer is B because this is the only one where both numerator and denominator don't have a common factor or can be changed into a mixed number.

A skier has decided that on each trip down a slope, she will do 2 more jumps than before. On her first trip she did 6 jumps. Derive the sigma notation that shows how many total jumps she attempts from her fourth trip down the hill through her twelfth trip. Then solve for how many total jumps she attempts from her fourth trip down the hill through her twelfth trip.I tried to answer, but I don't really know how to even set it up... :/

Answers

The correct answers are:

Explanation:

Since she is adding two more jumps every time she goes down hill, this is an arithmetic sequence. The general form of an arithmetic sequence is

Since we want the number of jumps on her 4th through 12th trips, we will set n in the summation from 4 to 12. n=4 goes at the bottom of Σ and 12 goes at the top, to represent the values we are interested in.

Beside this, we write our general form. The first term is 6 and d, the common difference, is 2. This gives us 6+2(n-1) beside the summation:

\Sigma_(n=4)^(12) 6+2(n-1)

To evaluate this, we substitute the values 4, 5, 6, 7, 8, 9, 10, 11 and 12 in for n, adding all of the values together:

6+2(4-1)+6+2(5-1)+6+2(6-1)+6+2(7-1)+6+2(8-1)+6+2(9-1)+6+2(10-1)+6+2(11-1)+6+2(12-1)

=6+6+6+8+6+10+6+12+6+14+6+16+6+18+6+20+6+22

=180
I'll just manually compute this one. Every attempt she will add 2 more jumps.

Attempt           Jumps       Accumulated Jumps
1                          6                         6
2                          8                       14
3                         10                      24
4                         12                      36
5                         14                      50
6                         16                      66 
7                         18                      84
8                         20                    104
9                         22                    126
10                       24                    150
11                       26                    176
12                       28                    204

Total jumps from 4th trip through 12th trip: 204 - 24 = 180 jumps

Find the unknown value of 5/25 = 13/

Answers

65, since 25/5=5.
13*5=65
The unknown value is 65. All of my work is in this image. And if my answer was helpful, please choose my answer as the brainliest one. Thank you!!!
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