CHEMISTRY MIDDLE SCHOOL

A container of hydrogen at 172 kpa was decreased to 85.0 kpa producing a new volume of 765 mL. What was the original volume

Answers

Answer 1
Answer:

Answer:

\boxed{\text{378 mL}}

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p_(1)V_(1) = p_(2)V_(2)

Data:

\begin{array}{rclrcl}p_(1)& =& \text{172 kPa}\qquad & V_(1) &= & \text{?} \np_(2)& =& \text{85.0 kPa}\qquad & V_(2) &= & \text{765 mL}\n\end{array}

Calculations:

\begin{array}{rcl}172V_(1) & =& 85.0 * 765\n172V_(1) & = & 65 025\nV_(1) & = &\textbf{378 mL}\n\end{array}\n\text{The original volume was } \boxed{\textbf{378 mL}}

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