Answer:
Waft
Explanation:
You should waft you hand from the tube to your face you should never smell directly or it could harm you hope this helped :)
Whenever dealing with any chemicals it is important to wear safety googles, gloves, safe cloths, and especially a safety mask. You never know how bad can the chemicals harm your body, so its important for you to not inhale them or even get contact with any part of your body. The most safely way to observe the odor of a chemical in a test tube, you should always were safety gears.
Hope this Helps!
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a. Reduction
b. Decomposition
Oxidation
d. Acid-Base Netralization
Answer:
The correct answer is reduction.
Explanation:
Nitrogen gas reacts with hydrogen gas and get reduced to form ammonia. In this reaction.This is important reaction of atmospheric nitrogen fixation.The reaction is carried out by many nitrogen fixing bacteria such as Azotobacter,Clostridium etc.
N2+3H2+6e- = 2NH3
The reaction N2 + 6e → 2N-3 represents reduction, where nitrogen gains electrons to form N-3 ions.
The reaction N2 + 6e → 2N-3 represents reduction. In this reaction, nitrogen (N2) gains electrons (e) to form N-3 ions. Reduction is a process in which an atom or ion gains electrons, resulting in a decrease in its oxidation state.
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The number of molecules of isopently acetate is 4.63 x 10¹⁵ molecules
calculation
Step 1: find the moles of isopently acetate( C₇H₁₄O₂)
moles = mass÷ molar mass
From periodic table the molar mass of C₇H₁₄O₂
= (12 x7 ) + (1 x14) +(16 x2) =130 g/mol
moles = 1 x10⁻⁶ g÷ 130 g/mol = 7 x 10⁻⁹ moles
step 2 ; use the Avogadro's law constant to calculate the number of molecules
That is according to Avogadro's law 1 mole = 6.02 x 10²³ molecules
7 x 10⁻⁹ moles = ? molecules
by cross multiplication
= { (7 x 10⁻⁹ moles x 6.02 x10²³ molecules) / 1 mole} = 4.63 x 10¹⁵ molecules
Answer:
This number has 3 significant figures.
Explanation:
a. How many grams of Na20 are produced when 57.5 g of Na
reacts ?
b. If you have 18.0 g of Na, how many grams of O2 are
required for reaction?
c. How many grams of O2 are needed in a reaction that
produces 75.0 g of Na2O?
Answer:
Explanation:
a )
4Na(s) + O₂(g) - - 2Na₂O(s)
4 x 23g 32g 2x62
92 g of Na produces 124 g of Na₂O(s)
57.5 g of Na produces (124 / 92) x 57.5
= 77.5 g of Na₂O(s)
b )
92 g of Na requires 32 g of O₂
18 g of Na requires ( 32 / 92 ) x 18
= 6.26 g of O₂
c )
128 g of Na₂O(s) requires 32 g of O₂
75 g of Na₂O(s) requires ( 32 / 128 ) x 75
= 18.75 g of O₂