To safely observe the odor of a chemical in a test tube you should?

Answers

Answer 1
Answer:

Answer:

Waft

Explanation:

You should waft you hand from the tube to your face you should never smell directly or it could harm you hope this helped :)

Answer 2
Answer:

Whenever dealing with any chemicals it is important to wear safety googles, gloves, safe cloths, and especially a safety mask. You never know how bad can the chemicals harm your body, so its important for you to not inhale them or even get contact with any part of your body. The most safely way to observe the odor of a chemical in a test tube, you should always were safety gears.

Hope this Helps!

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a ball is rolling across the floor.How could you apply an unbalanced force to change the speed or direction of the ball?
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True or false: This balanced equation shows the combustion of ethane: 2C2H6 + 7O2 → 4CO2 + 6H2O
Which phenomena naturally warms earth lower atmosphere and surface?
Compozitia procentuala a NaCl

Are spider multicellular

Answers

Yes, the only single cell organisms that exist are the cells that make up an organism

N2 + 6e → 2N-3The reaction above represents which of the following?
a. Reduction
b. Decomposition
Oxidation
d. Acid-Base Netralization​

Answers

Answer:

The correct answer is reduction.

Explanation:

Nitrogen gas reacts with hydrogen gas and get reduced to form ammonia. In this reaction.This is important reaction of atmospheric nitrogen fixation.The reaction is carried out by many nitrogen fixing bacteria such as Azotobacter,Clostridium etc.

        N2+3H2+6e-  =  2NH3

Final answer:

The reaction N2 + 6e → 2N-3 represents reduction, where nitrogen gains electrons to form N-3 ions.

Explanation:

The reaction N2 + 6e → 2N-3 represents reduction. In this reaction, nitrogen (N2) gains electrons (e) to form N-3 ions. Reduction is a process in which an atom or ion gains electrons, resulting in a decrease in its oxidation state.

Learn more about Reduction here:

brainly.com/question/33512011

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How many molecules of isopently acetate C7H1402 are released (1x10^ -6g) in a typical bee sting

Answers

The  number of molecules of isopently acetate is  4.63  x 10¹⁵  molecules

 calculation

Step 1:  find the moles of isopently acetate( C₇H₁₄O₂)

moles  =  mass÷  molar mass

From periodic table the molar mass of C₇H₁₄O₂

= (12 x7 ) + (1 x14) +(16 x2) =130 g/mol

moles = 1 x10⁻⁶ g÷ 130 g/mol =  7  x 10⁻⁹ moles

step 2 ; use the Avogadro's  law  constant to calculate the number of molecules

That  is according to Avogadro's law  1 mole  = 6.02 x 10²³  molecules

                                                          7 x 10⁻⁹ moles = ?  molecules

by cross multiplication

= { (7 x 10⁻⁹ moles x  6.02 x10²³  molecules) / 1  mole} = 4.63 x 10¹⁵  molecules

How many sig figs does the number 0.000203 have?

Answers

Answer:

This number has 3 significant figures.

Explanation:

Examples of a cell wall

Answers

Answer: A example of this is a wall surrounding fungi (a cell wall)


- - Why?
Because this is a good example of a cell wall, and it is commonly used in most science lessons (in  my school atleast)



✡Hope this helps


a gate protecting the house inside 

Sodium reacts with oxygen to produce sodium oxide.4Na(s) + O2(g) - - 2Na2O(s)
a. How many grams of Na20 are produced when 57.5 g of Na
reacts ?
b. If you have 18.0 g of Na, how many grams of O2 are
required for reaction?
c. How many grams of O2 are needed in a reaction that
produces 75.0 g of Na2O?

Answers

Answer:

Explanation:

a )

4Na(s) + O₂(g) - - 2Na₂O(s)

4 x 23g    32g           2x62

92 g of Na produces 124 g of Na₂O(s)

57.5 g of Na produces (124 / 92) x 57.5

= 77.5 g of Na₂O(s)

b )

92 g of Na requires 32 g of O₂

18 g of Na requires ( 32 / 92 ) x 18

= 6.26 g of O₂

c )

128 g of Na₂O(s) requires 32 g of O₂

75 g of Na₂O(s) requires ( 32 / 128 ) x 75

= 18.75 g of O₂