C. 28.26 cm 2
Diameter = 2 * Radius (r) Area of the circle radius. The radius of the circle calculator uses the following area of the circle formula, Area of a circle = π * r 2
Area = π· ( d2) 2 = 3.14· ( 62) 2 = 3.14· (3) 2 = 28.27 square centimeters (*) Area = C2 4π = 18.852 4π = 355.32(4·3.14) = 355.3212.56 = 28.27 square centimeters (*)
The first formula is A=πr², or the second formula is d=2r. Now, we could solve for a,
A=1/4πd²=1/4*π*6²=28.27433cm²,
Therefore, the solution is 28.26 cm 2
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b. The last book in the series borrowed from a classmate is quite long.
c. The last book in the series borrowed from a classmate, is quite long.
d. The last book in the series, borrowed from a classmate is quite long.
16 ounces of cat food was in the bag, on 24th day
Given : The y axis represents dependent variable ie the 'ounces of cat food' , and x axis represents independent variable ie 'days since bag was bought'
To find : Value of y ie ounces of food - on a particular value of x ie days since bag bought , we draw a straight vertical line from value of x to the curve & correspond it to y axis.
From x = 24, if we draw a straight vertical line to the graph - it touches the point ( x,y ) = (24, 16). Extending it further to y axis, we get value of y ie 'ounces of food' = 16
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Answer:
There were 16 ounces of Cat Food after 24 days.
Step-by-step explanation:
From the graph attached,
For an ordered pair (x, y) lying on the graph,
x-coordinate represents the number of days since bag was bought and y- coordinate represents the ounces of cat food required.
Now the value x = 24 on x-axis shows the number of days since the bag was bought.
For x = 24, ounces of cat food in the bag ( y ) = 16 ounce
Therefore, 16 ounces of Cat Food were in the bag after 24 days since it was bought.
hides his car on a side street that intersects the middle of the school zone and records the speed of each car that
passes through. The 36 cars that he recorded had an average speed of 16.33 mph with a sample standard deviation
of 2.54 mph.
Calculate the appropriate test statistic (Give as a decimal rounded to the nearest thousandth).
Answer: test statistic = 0.002
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 15
For the alternative hypothesis,
µ > 15
The inequality sign means that it is right tailed.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 36,
Degrees of freedom, df = n - 1 = 36 - 1 = 35
t = (x - µ)/(s/√n)
Where
x = sample mean = 16.33
µ = population mean = 15
s = samples standard deviation = 2.54
t = (16.33 - 15)/(2.54/√36) = 3.14
We would determine the p value using the t test calculator. It becomes
p = 0.002