Answer:10
Step-by-step explanation:
The cost of each adult ticket is $28, but there is no solution for the cost of each student ticket in this case.
To solve this problem, we can set up a system of equations using the given information. Let's represent the cost of an adult ticket as 'a' and the cost of a student ticket as 's'. From the first equation, we know that 4a + 2s = 64. From the second equation, we know that 3a + 3s = 60. Now we can solve this system of equations.
Multiplying both sides of the second equation by 2 gives us 6a + 6s = 120. We can subtract the first equation from this equation to eliminate 's'.
6a + 6s - (4a + 2s) = 120 - 64
Expanding and simplifying the equation gives us 2a = 56. Dividing both sides by 2, we find that a = 28. Now we can substitute this value into either of the original equations to find 's'.
Using the first equation: 4(28) + 2s = 64
Simplifying the equation gives us 112 + 2s = 64
Subtracting 112 from both sides gives us 2s = -48. Dividing both sides by 2, we find that s = -24.
However, since we're talking about the cost of tickets, we can't have a negative value. Therefore, there is no solution for 's' in this case.
The cost of each adult ticket is $28, but there is no solution for the cost of each student ticket in this case.
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Answer:
6,786,083.5
Step-by-step explanation:
Since we are looking for distance, we have to convert the 2nd part (which is the speed) to dostance.
Distance = speed x time
Distance = 5 x 2.25 = 11.25
In the first part, he drove for 3.5 hours. And in the 2nd part, he drove for 2.25 hours which sum up together to be 5.75 hours.
Since we have the distances for both parts now, we just sum it up
which it 168 + 11.25 = 179.25 miles
I hope this is good
Hi,
x= 20/3
Have a great day!
Answer:
A square is a quadrilateral with all sides equal in length and all interior angles right angles. Thus a rhombus is not a square unless the angles are all right angles. A square however is a rhombus since all four of its sides are of the same length.
Step-by-step explanation:
Hope thats helpful! :)
you can find the answer to this by looking at the properties of both shapes. a rhombus has Opposite sides that are parallel, Adjacent angles are supplementary, All the four sides are equal, and all 4 sides bisect forming right angles. a square also has these properties therefore a square can classify as a rhombus. but be careful, just because a square is a rhombus, it doesn't always necessary mean that a rhombus is always a square