Answer:
4j^3 + 5j^2 + 7j - 1
Step-by-step explanation:
(8j^3 - 3j^2 + 5)-(4j^3+8j^2+7j-6)
Distribute the -1 in front of the (4j^3+8j^2+7j-6)
8j^3 - 3j^2 + 5 - 4j^3 + 8j^2 + 7j - 6
We can combine anything with the same exponent number that "j" is raised to
8j^3 - 4j^3 = 4j^3
-3j^2 + 8j^2 = 5j^2
7j is just 7j since there is nothing else with just j in it
5 - 6 = -1
Add these together
4j^3 + 5j^2 + 7j - 1 is our final answer
-p+3+2p-2p
1.2 Multiply (3-2p) by (3-2p)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (3-2p) and the exponents are :
1 , as (3-2p) is the same number as (3-2p)1
and 1 , as (3-2p) is the same number as (3-2p)1
The product is therefore, (3-2p)(1+1) = (3-2p)2
Answer:
x=4
Step-by-step explanation:
Step 1:-
given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.
AB = 2x and BC = 3(x+1) and longest side AC= 17
by using Pythagoras theorem
step 2:-
The hypotenuse is longest side is AC = 17 units
(17)^2 = 4x^2 +9(X+1)^2
on simplification, we will use formula
289 = 4x^2 +9(x^2+2x+1)
finding factors 70 X 52 = 3640
Taking common , we get
13x(x-4)+70(x-4)=0
x-4=0 and 13x+70=0
x=4 and
x=4 and
we can not choose negative value so x value is 4
Final answer:- x = 4
verification:-
289 = 4(4)^2+9(4+1)^2
289 = 64 +9(25)
289=289
Answer:
x = 4
Step-by-step explanation:
The length of two legs of a right angle triangle are 2x and 3(x+1).
The length of longest side is 17 units. It means measure of hypotenuse is 17 units.
According to the pythagoras theorem,
On splitting the middle terms we get
Using zero product property we get
The value of x can not be a negaive number, because for negative value of x the value of 2x is negative and side can not be negative.
Therefore, the value of x is 4.