Arun’s restaurant bill is $58, and he wants to leave the waiter an 18 percent tip. What will Arun’s total bill be?

Hello,

The median of the temperatures at Springwood is 86. (median is at the middle).

the median of the temperatures at Meadows is 73. (median is at the middle).

The (IQR) interquartile range of the temperatures at Meadows is 12. (You have to subtract both of the IQR left and right 80 - 68 = 12).

The (IQR) interquartile range of the temperatures at Springwood is 14. (You have to subtract both of the IQR left and right 91 - 77 = 14).

the difference of the medians as a multiple of their average interquartile range is 79.5 is average median and 13 average IQR.

Answer: The median of the temperatures at Springwood is 86.    

The median of the temperatures at Meadows is 73.  

The interquartile range of the temperatures at Meadows is 12.  

The interquartile range of the temperatures at Springwood is 14.

The difference of the medians as a multiple of their average interquartile range as : Difference in medians = 13= 1 x 13

i.e. Difference in medians  = 1 x (Average interquartile range)

Step-by-step explanation:

In a box - whisker plot , the vertical line in box represents the median value.

The left end of box denotes Lower quartile and the right end of the box Upper quartile.

By considering the given picture,

For Meadows ,

Median = 73

The median of the temperatures at Meadows is 73.                           (1)

Lower quartile = 68

Upper quartile = 80

Interquartile range = Upper quartile- Lower quartile

Interquartile range=80-68 = 12

The interquartile range of the temperatures at Meadows is 12.     (2)

For Springwood,

Median = 86

The median of the temperatures at Springwood is 86.                 (3)

Lower quartile = 77

Upper quartile = 91

Interquartile range = Upper quartile- Lower quartile

= 91-77 = 14

The interquartile range of the temperatures at Springwood is 14.         (4)

Difference in medians = 86-73 = 13              [From (1) and (3)]

Average interquartile range =    [From (2) and (4)]

The difference of the medians as a multiple of their average interquartile range as : Difference in medians = 13= 1 x 13

i.e. Difference in medians = 1 x (Average interquartile range)

Answer:

Option B. 6

Step-by-step explanation:

Jalen is buying a new car. His options are below:

Model : Compact, luxury, sport    = 3 options

Transmission : automatic, manual  =  2 options

Color : red, blue, black, yellow   =  4 options

Jalen decides that he wants a yellow car.

Now he has total number of choices = 3 × 2 = 6 choices

Option B. 6 choices is the answer.