An ordinary deck of playing cards has 52 cards. There are four suitsspades, hearts, diamonds, and clubswith 13 cards in each suit. Spades and clubs are black; hearts and diamonds are red. One of these cards is selected at random. Let A denote the event that is chosen. Find the probability that is chosen, and express your answer in probability notation.

Answers

Answer 1

Answer:

Complete question is;

An ordinary deck of playing cards has 52 cards. There are four suits

-spades, hearts, diamonds, and clubs

-with 13 cards in each suit.

Spades and clubs are black; hearts and diamonds are red. One of these cards is selected at random. Let A denote the event that a red card is chosen.

Find the probability that a red card is chosen, and express your answer in probability notation.

Answer:

P(A) = 0.5

Step-by-step explanation:

We are told that the ordinary deck of playing cards has 52 cards.

Now, there are four suits

-spades, hearts, diamonds, and clubs

-with 13 cards in each suit.

Now, in a standard set of playing cards, there are 13 black spades and 13 black clubs as well as 13 red hearts and 13 red diamonds

Thus;

Number of red cards = 13 + 13

Thus;

Number of red cards = 26

Since, A denotes the event that red card is chosen.

This means that probability of choosing a red card is;

P(A) = number of red cards/total number in a deck of cards

P(A) = 26/52

P(A) = 0.5

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Find an exact value cos(19pi/12)

Answers

$cos\left ( (9\pi)/(12)\right )=\frac{\sqrt{2-√(3)}}{2}$

Step-by-step explanation:

We know that

cos 2x = 2cos²x - 1

So we have

$cosx=\sqrt{(1+cos2x)/(2)}$

Substituting $x=(19\pi)/(12)$

$cos\left ( (19\pi)/(12)\right )=\sqrt{(1+cos2\left ( (19\pi)/(12)\right ))/(2)}\n\ncos\left ( (19\pi)/(12)\right )=\sqrt{(1+cos\left ( (19\pi)/(6)\right ))/(2)}\n\ncos\left ( (9\pi)/(12)\right )=\sqrt{(1+cos570)/(2)}\n\ncos\left ( (9\pi)/(12)\right )=\sqrt{(1-(√(3))/(2))/(2)}\n\ncos\left ( (9\pi)/(12)\right )=\sqrt{(2-√(3))/(4)}\n\ncos\left ( (9\pi)/(12)\right )=\frac{\sqrt{2-√(3)}}{2}$

$cos\left ( (9\pi)/(12)\right )=\frac{\sqrt{2-√(3)}}{2}$

19 π / 12 = 19 * 180° / 12 = 285 °
cos ( 19 π / 12 ) = cos 285° = cos ( - 75° ) = cos 75°
cos 75° = cos ( 45° + 30° ) = cos 45° cos 30° - sin 45° sin 30° =
= ( √2 / 2 · √3/2 ) - ( √2 / 2 · 1/2 ) = √6/4 - √2/4 =
= ( √6 - √2 )/ 4

5x + 4x - 4x plz help me

Answers

the answer is 5x
hipe that helps

5x is the answer because 4x-4x=0 and 5x+0=5x.

Hy! (√2+1)²+(3-√3)²-(√5+1)²=???
Thank yours!:*

Answers

$(\sqrt2+1)^2+(3-\sqrt3)^2-(\sqrt5+1)^2=\n2+2\sqrt2+9-6\sqrt3+9-(5+2\sqrt5+1)=\n20+2\sqrt2-6\sqrt3-5-2\sqrt5-1=\n14+2\sqrt2-6\sqrt3-2\sqrt5$

Misha and Dontavious were asked to solve the following problem using linear programming. A local school district can operate a large bus for $300 per day and a small bus for $200 per day. The district needs to arrange transportation for at least 360 students for a field trip and has enough chaperones to have one chaperone per bus for up to 7 buses. Each large bus can hold 60 students and each small bus can hold 45 students. What is the minimum cost for the transportation for the field trip?