Subtract and simplify: (3x^2 + 7) – (x^2 – 6x – 4)Question 3 options:

2x^2 + 6x + 3


4x^2 – 6x + 3


2x^2 + 6x + 11


4x^2 + 3

Answers

Answer 1
Answer: Distribute the Negative Sign:=3x2+7+−1(x26x−4)=3x2+7+−1x2+−1(6x)+(−1)(−4)=3x2+7+x2+6x+4Combine Like Terms:=3x2+7+x2+6x+4=(3x2+x2)+(6x)+(7+4)
Answer is 
=2x2+6x+11

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When critiquing an observational study, which four factors should be analyzed?A.Methodology, Results, Discussion, ConclusionB.Introduction, Results, Discussion, ConclusionC.Introduction, Methodology, Results, DiscussionD.Methodology, Causes, Results, Discussion this was in my math class, so that is why the subject is mathematics. Any help would be greatly appreciated.

Determine the discriminant for the quadratic equation 0=-2x^2+3 Based on the discriminant value, how many real numbersolutions does the equation have?

Answers

Answer:

This problem has two number solutions. The solutions are x = ±√ 1.500 = ± 1.22474.

Step-bystepexplanation:

Step 1 :

Equation at the end of step 1 :

0 - ((0 - 2x2) + 3) = 0

Step 2 :

Trying to factor as a Difference of Squares :

2.1 Factoring: 2x2-3

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 2 is not a square !!

Ruling : Binomial can not be factored as the

difference of two perfect squares

Equation at the end of step 2 :

2x2 - 3 = 0

Step 3 :

Solving a Single Variable Equation :

3.1 Solve : 2x2-3 = 0

Add 3 to both sides of the equation :

2x2 = 3

Divide both sides of the equation by 2:

x2 = 3/2 = 1.500

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

x = ± √ 3/2

The equation has two real solutions

These solutions are x = ±√ 1.500 = ± 1.22474

Consider the polynomial P(x)=x⁴+3x³-28x²-36x+144. Write the equation of P in factored form.

Answers

Answer:

P(x)=(x-2)(x-4)(x+3)(x+6)

Step-by-step explanation:

Given: P(x)=x⁴+3x³-28x²-36x+144

It is a polynomial with degree 4.

It should maximum four factor.

Hit and trial error method.

Put x = 2 into P(x)

P(2)=2⁴+3×2³-28×2²-36×2+144

P(2) = 0

So, x-2 would be factor of P(x)

Now divide x⁴+3x³-28x²-36x+144 by x-2 to get another factors

(x^4+3x^3-28x^2-36x+144)/ (x-2) = x^3+5x^2-18x-72

P(x)=(x-2)(x^3+5x^2-18x-72)

Put x = 4

P(4) = 0

now divide x^3+5x^2-18x-72 by x-4

(x^3+5x^2-18x-72)/ (x-4) = x^2+9x+18

P(x)=(x-2)(x-4)(x^2+9x+18)

Now factor x^2+9x+18

\Rightarrow x^2+9x+18

\Rightarrow (x+6)(x+3)

Complete factor of P(x)

P(x)=(x-2)(x-4)(x+3)(x+6)

Find the product of 1/6 x 3

Answers

Answer: 0.5 or 3/6 or 1/2

Step-by-step explanation:

1/6 x 3 = 1/6 + 1/6+ 1/6 = 3/6 = 1/2

L is the midpoint of MN¯¯¯¯¯¯¯, ML=2x+7 and LN=3x−3. Find ML, LN, and MN.

Answers

Answer:

ML=27\nLN=27\nMN=54

Step-by-step explanation:

Since L is the midpoint of MN, by the definition of midpoint:

ML=LN

We can picture the following segment:

M----------L----------N

We know that ML=2x+7 and LN=3x-3. Since the two segments are equivalent, we can set them equal to each other:

2x+7=3x-3

Now, let's solve for x. Subtract -7 from both sides:

2x=3x-10

Subtract 3x from both sides:

-x=-10

Divide both sides by -1:

x=10

So, the value of x is 10.

With this, we can find the remaining lengths.

We know that ML is 2x+7.

Substitute 10 for x. So, the length of ML is:

ML=2(10)+7=20+7=27

We know that LN is 3x-3. So, the length of LN is:

LN=3(10)-3=30-3=27

Finally, MN will be the combined lengths of ML and LN. So:

MN=ML+LN=27+27=54

And we're done!

The lengths of each segment are:

ML = 27, LN = 27, and MN = 54.

We have,

Let's use the information given to find the values of ML, LN, and MN.

ML = 2x + 7

LN = 3x - 3

L is the midpoint of MN, which means that ML is equal to LN:

2x + 7 = 3x - 3

Now, let's solve for x:

Move the x term to one side of the equation:

2x - 3x = -3 - 7

-x = -10

Now, multiply both sides by -1 to get rid of the negative sign:

x = 10

Now that we have the value of x, we can find the lengths ML, LN, and MN:

ML = 2x + 7

ML = 2(10) + 7

ML = 20 + 7

ML = 27

LN = 3x - 3

LN = 3(10) - 3

LN = 30 - 3

LN = 27

MN = ML + LN

MN = 27 + 27

MN = 54

Thus,

The lengths of each segment are:

ML = 27, LN = 27, and MN = 54.

Learn more about midpoints of linesegments here:

brainly.com/question/13792156

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Peter uses unit cubes to build a figure in the shape of the letter x. What is the fewest unit cub es that peter can use to build the figure?

Answers

X letter is formed by two lines. The minimum amount of cubes that one side may have to look a line that cross other line is 3, but given that one cube is shared by the two lines you only need 5 cubes. So the answer is that the fewest unit cubes that Peter can use to build the figue in the shpe of X is 5 cubes.

The ratio of the same side interior angles of two parallel lines is 1:14. Find the measures of all eight angles formed by the parallel lines and transversal. Sorry! Would appreciate if you give the answer by Tuesday! Thanks

Answers

Given that the same-side interiorangles formed by two parallel lines and a transversal have an angle ratio of 1:14, the eight angles formed are:

m<1 = 12°

m<2 = 168°

m<3 = 168°

m<4 = 12°

m<5 = 12°

m<6 = 168°

m<7 = 168°

m<8 = 12°

Applying the knowledge of ratio, transversal and parallel lines, we can determine the measures of all 8 angles that are formed when a transversal intersects two parallel lines as shown in the image attached below.

Let < 1 and < 6 be the two same-side interior angles whose measures are in the ratio, 1:14.

Thus:

  • m<1 : m<6 = 1 : 14

Recall:

Same-side interior angles are always supplementary. That is,

m<1 + m<6 = 180 degrees.

Let's apply ratio to find the measure of <1 and <6.

  • m<1 = ratio of <1 / sum of ratio x 180

m \angle 1 = (1)/(1 + 14) * 180\n\nm \angle 1 = (1)/(15) * 180\n\nm \angle 1 = 12^(\circ)

  • m<6 = ratio of <6 / sum of ratio x 180

m \angle 6 = (14)/(1 + 14) * 180\n\nm \angle 6 = (14)/(15) * 180\n\nm \angle 6 = 168^(\circ)

Since we know the measure of <1 and <6, we can find the measure of others as follows:

  • m<2 = m<6 = 168° (corresponding angles are congruent)

  • m<3 = m<6 = 168° (alternate interior angles are congruent)

  • m<4 = m<1 = 12° (vertical angles are congruent)

  • m<5 = m<1 = 12° (corresponding angles are congruent)

  • m<7 = m<6 = 168° (vertical angles are congruent)

  • m<8 = m<4 = 12° (corresponding angles are congruent)

In conclusion, given that the same-side interiorangles formed by two parallel lines and a transversal have an angle ratio of 1:14, the eight angles formed are:

m<1 = 12°

m<2 = 168°

m<3 = 168°

m<4 = 12°

m<5 = 12°

m<6 = 168°

m<7 = 168°

m<8 = 12°

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Answer:

At the intersection of the first parallel line with the transversal, a = 12°, c = 168°, d = 12°, e = 168°. Counting counterclockwise from a.

At the first intersection of the second parallel line with the transversal, b = 168°, f = 12°, g = 168°, h = 12°. Counting clockwise from b.

Step-by-step explanation:

Let a be the first interior angle. Since they are in 1:14, the second same side interior angle is b = 14a.

We know that the sum of interior angles equals 180°.

So, a + b = 180°

a + 14a = 180°

15a = 180°

a = 180/15

a = 12°

At alternate angle to the other interior angle, b adjacent to a is c = b = 14a = 14 × 12 = 168°

The angle vertically opposite to a is d = a = 12°

The angle vertically opposite to a is b = e = 168°

At the intersection of the second parallel line and the transversal, the angle alternate to a is f = a = 12°

the angle vertically opposite to angle b is g = b = 168°

the angle vertically opposite to f is h = 12°