MATHEMATICS HIGH SCHOOL

The information given represents lengths of sides of a right triangle with c the hypotenuse. Find the correct missing length to the nearest hundredth. A calculator may be helpful.a = 20, b = 28, c = ?


A.34.41


B.35.45


C.35.88


D.34.72

Answers

Answer 1
Answer: The correct answer for the question that is being presented above is this one: "A.34.41." The information given represents lengths of sides of a right triangle with c the hypotenuse. 

h^2 = a^2 + b^2
c^2 = 20^2 + 28^2
c^2 = 400 + 784
c^2 = 1184
c = 34.41

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There were 3 times as many baby dinosaurs as adult dinosaurs. what does that mean?

Answers

It means , however, many dinos there are times it by 3 to get your answer for the baby dinos

Answer:

Times how ever many adult dinosaurse by 3 to get how ever many baby dinos there are

Step-by-step explanation:

Round all the way 2689

Answers

2689

rounded to the nearest tens = 2690
rounded to the nearest hundreds = 2700
rounded to the nearest thousands = 3000

If the number before the place it needs to be round off is 5 and above, then it is rounded up. If the number is 4 and below, it is rounded down.

For example: 
2444 

rounded to the nearest tens = 2440
rounded to the nearest hundreds = 2400
rounded to the nearest thousands = 2000

use the counting principle to find the probability of choosing the 8 winning lottery numbers when the numbers are chosen at random from 0 to 9

Answers

Answer: 1/10^8

Step-by-step explanation:

Here the total numbers are 10 ( 0, 1, 2, 3, 4, 5, 6, 7, 8, 9)

Since, the probability of choosing one number = (1)/(10)

Therefore, the probability of choosing 8 numbers =

(1)/(10)*(1)/(10)* (1)/(10)* (1)/(10)* (1)/(10)* (1)/(10)* (1)/(10)* (1)/(10)* ( because there is no replacement)

= (1)/(10^8)
The total feasible numbers are: 10*10*10*10*10*10*10*10 = 10^8

The probability is 1/10^8

For what values a is the equation (1/a+2)=(1/a)+(1/2) true?

Answers

There is no value of 'a' that makes the equation true. 
In other words, the equation has no solution.

Here's how you can tell:

                                           (1/a + 2)  =  (1/a) + (1/2)

Eliminate parentheses:      1/a + 2  =  1/a   +   1/2

Subtract  1/a  from
each side:                                      2  =                1/2

Is there any value of  'a'  that can make  2 = 1/2 ?
I can't think of one.
So the equation has no solution.

Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas. He starts by assigning coordinates as given.A right triangle is graphed on a coordinate plane. The horizontal x-axis and y-axis are solid, and the grid is hidden. The vertices are labeled as M, K, and L. The vertex labeled as M lies on begin ordered pair 0 comma 0 end ordered pair. The vertex labeled as K lies on begin ordered pair 0 comma 2 b end ordered pair. The vertex labeled as L lies on begin ordered pair 2a comma 0 end ordered pair. A bisector is drawn from point M to the line KL. The intersection point on line KL is labeled as N.

Enter the answers to complete the coordinate proof.
N is the midpoint of KL¯¯¯¯¯KL¯ . Therefore, the coordinates of N are (a,
).

To find the area of △KNM△KNM , the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM△KNM is
.

To find the area of △MNL△MNL , the length of the base ML is
, and the length of the height is
. So an expression for the area of △MNL△MNL is ab.

Comparing the expressions for the areas shows that the areas of the triangles are equal.

Answers

The coordinates of N is (a,b) using the midpoint formula.
The area for △KNM is (1/2)(a)(2b) = ab
The area of △MNL is ab.
Since the area of △KNM = △MNL and the area of △KML is 2ab, then we have proved that a segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

1. N is a midpoint of the segment KL, then N has coordinates

\left((x_K+x_L)/(2),(y_K+y_L)/(2) \right) =\left((0+2a)/(2),(2b+0)/(2) \right) =(a,b).

2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is

A_(KMN)=(1)/(2)\cdot \text{base}\cdot \text{height}=(1)/(2)\cdot 2b\cdot a=ab.

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

A_(MNL)=(1)/(2)\cdot \text{base}\cdot \text{height}=(1)/(2)\cdot 2a\cdot b=ab.

4. Comparing the expressions for the areas you have that the area A_(KMN) is equal to the area A_(MNL). This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

Divide. Express your answer in simplest form.
11/12 divided by 3/4

Answers

11/12 : 3/4 =11/12 *4/3 =11/9
before go to 11/9, you have to simplify the answer
11/12 divided by 3/4

11/12 • 4/3 (multiply by the reciprocal)
OR
Multiply from top to bottom
(11•4) • (12•3) = 44/36

Simplify (Divide top and bottom by the highest common factor... which in this case is 4)

Answer: 11/9
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