The possible combination in which the app can be downloaded in ipod is or .
Further explanation:
The total memory space available in the ipod is .
The memory space required for the pedometer app is .
The memory space required for a photo app is .
The memory space required for a math app is .
As per teh question meyer wants to download the app as mentioned above in his ipod.
So, in order to download the app the most important point is that the total memory space available in the ipod should no be less than the memory space required for all the apps.
The objective is to determine the combination in which the different app can be stored in the ipod.
Consider three cases for the given question.
Case 1:
Consider that all the three apps are needed to be downloaded in the ipod.
If all the three apps are required to be downloaded then the total memory space required is calculated as follows:
As per the above calculation it is concluded that the all the three apps requires a memory space of .
Since, the total free memory space available in the ipod is and so, this case is not possible.
Therefore, it is not possible to download all the three apps in ipod.
Case 2:
Consider that only pedometer app and a photo app is required to be downloaded.
The memory space required by pedometer app and a photo app is calculated as follows:
As per the above calculation it is concluded that the photo app and pedometer app requires a memory space of .
Since, the total free memory space available in the ipod is and so, this case is not possible.
Therefore, it is not possible to download pedometer app and a photo app in ipod.
Case 3:
Consider that only pedometer app and a math app is required to be downloaded.
The memory space required by pedometer app and a math app is calculated as follows:
As per the above calculation it is concluded that a math app and a pedometer app requires a memory space of .
Since, the total free memory space available in the ipod is and so, this case is possible.
Therefore, it is possible to download pedometer app and a math app in ipod.
Case 4:
Consider that only a photo app and a math app is required to be downloaded.
The memory space required by math app and a photo app is calculated as follows:
As per the above calculation it is concluded that the photo app and pedometer app requires a memory space of .
Since, the total free memory space available in the ipod is and so, this case is not possible.
Therefore, it is not possible to download math app and a photo app in ipod.
This implies that either meyer can download pedometer app and math app or only a photo app.
Thus, the possible combination in which the app can be downloaded in ipod is or .
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Answer details:
Grade: Junior school
Subject: Mathematics
Chapter: Simplification
Keywords: Combination, simplification, meyer, memory, download, app, photo app, pedometer app, GB, 0.64, 0.24, math app, ipod.
Answer:
No Solutions
There is no possible value for x that could make this true. If you take a number and add 4 to it, it will never be the same as if you take the same number and add 3 to it. Such an equation is called a contradiction, because it cannot ever be true.
Step-by-step explanation:
We know that the perimeter of a rectangle is twice the length, plus twice the width.
P = 2L + 2W
We also know that the perimeter is 156.
P = 156
Finally, we know that the width is 12 less than the length.
W = L - 12.
The next thing that we do is substitute the information that we have into the original equation:
P = 2L + 2W
156 = 2L + 2(L - 12)
From this point we start to solve
156 = 2L + 2L - 24 <---we multiplied the '2' through the parenthesis
156 + 24 = 2L + 2L - 24 + 24
180 = 2L + 2L <--- getting like terms on same sides
180 = 4L <---combining like terms
180/4 = 4L/4 <--- getting like terms on same sides
45 = L <---now we have a value for L
Now we take the known value for L and substitute it in to our equation for W
W = L - 12
W = 45 - 12
W = 33
So now we have Length = 45 and Width = 33.
w = l - 12
156 = 2l + 2w
Since we have a value of w, we can plug that into the variable w to find the exact value of l.
156 = 2l + 2(l - 12)
Distributive property.
156 = 2l + 2l - 24
Combine like terms.
156 = 4l - 24
Add 24 to both sides.
180 = 4l
Divide both sides by 4.
l = 45
Now that we have the exact value of l, we can find the exact value of w.
w = l - 12
w = 45 - 12
w = 33
We now know the width is equal to 33 cm, and the length is equal to 45 cm. (This is your answer.)
We can verify by plugging these values into the second equation.
156 = 2l + 2w
156 = 2(45) + 2(33)
156 = 90 + 66
156 = 156 √ this is correct.
Answer:
1+2a
Step-by-step explanation:
To find the midpoint, add the two points together and divide by 2
(1+ 1+4a) /2 = (2+4a)/2 = 2/2 + 4a/2 =1 +2a