If r=9in then what is the volume of a cone

Answers

Answer 1
Answer: If the radius of the cone is 9 inches,
then the volume of the cone is

    (81 pi) x (the height of the cone, inches)                 cubic inches

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Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?

Answers

       5x = 6x² - 3
5x - 5x = 6x² - 5x - 3
         0 = 6x² - 5x - 3
         x = -(-5) ± √((-5)² - 4(6)(-3))
                              2(6)
         x = 5 ± √(25 + 72)
                        12
         x = 5 ± √(97)
                   12
          x = 5 + √(97)    U    x = 5 - √(97)
                     12                          12
the\ values\ of\ x\ is\ (5 +/- √(97))/(12).

The value of x are;  x = 5 + √(97)/12  and x = 5 - √(97)/12.

What is a quadratic equation?

A quadratic equation is the second-order degree algebraic expression in a variable.

The standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

Given;

 5x = 6x² - 3

Subtract 5x on both sides

5x - 5x = 6x² - 5x - 3

0 = 6x² - 5x - 3

       

x = -(-5) ± √((-5)² - 4(6)(-3)) / 2(6)

                           

x = 5 ± √(25 + 72)/ 12

x = 5 ± √(97)/ 12

               

The value of x are;

x = 5 + √(97)/12      

x = 5 - √(97)/12

                   

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What is the value of the dependent variable if the value is 0? f(x)=-13x2+5x-2x+8

Answers

f(0)=-13\cdot0^2+5\cdot0-2\cdot0+8=8

Quadrilateral EFGH has coordinates E(a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of HG.A (2a, 0)
B (a, 2a)
C (a, a)
D (a, 0)

Answers

Midpoint of HG = ((0 + 2a)/2, (0 + 0)/2) = (2a/2, 0/2) = (a, 0)
option D is the correct answer.
Coordinates are: H ( 0, 0 ) and G ( 2 a, 0 ).
Coordinates of the midpoint are:
x  = ( x 1 + x 2  ) / 2
y = ( y 1 + y 2 ) / 2
The midpoint of HG:
x = ( 0 + 2 a ) / 2 = 2 a / 2 = a
y = ( 0 + 0 ) / 2 = 0 / 2 = 0
Answer:
D ) ( a, 0 ) 

A sample of liquid has a mass of 24g and a volume of 16ml what is the density of the liquid

Answers

The density of the liquid will be 1500 kg per cubic meter.

What is density?

The density is the ratio of mass to volume of any substance.

Let m be the mass of the object and v be the volume of the object.

Then the density D will be

D = m / v      kg / cubic m

More the density means the number of the molecules will be more in a unit volume.

A sample of liquid has a mass of 24g and a volume of 16ml.

We know that one kg equals to 1000 grams.

24 g = 0.024 kg

We know that one ml equal to 10⁻⁶ cubic meters.

16 ml = 16 × 10⁻⁶ cubic meters

Then the density of the liquid will be

Density = 0.024 / 16 × 10⁻⁶

Density = 1500 kg per cubic meter

Thus, the density of the liquid will be 1500 kg per cubic meter.

More about the density link is given below.

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density = mass/volume

so,
24g/16ml = 1.5g per cm^3

1mL = 1cm^3

Solve for y: 3/4(5x-y)<3

Answers

(3)/(4)(5x-y) < 3\ \ \ /\cdot(4)/(3)\n\n(4)/(3)\cdot(3)/(4)(5x-y) < (4)/(3)\cdot3\n\n5x-y < 4\ \ \ /-5x\n\n-y < 4-5x\ \ \ /\cdot(-1) < 0\ then\

------------------------\ny=5x-4\n\nfor\ x=0\to y=5\cdot0-4=0-4=-4\to A(0;-4)\n\nfor\ x=2\to y=5\cdot2-4=10-4=6\to B(2;\ 6)\n------------------------\n\nlook\ at\ the\ picture

Give an example of a relation that is NOT a function and explain why it is not a function.I do not understand how to do this...please help its algebra.

Answers

The desired example is this: x=y^2
Because for each x>0 we have two different possible y values which means it is not a function anymore. a function should only maximum 1 y value for each x value.

You can see the above relation has multiple possible values for y because if we take x=1 then y can be -1 or 1.