B.mantle convection
C.subduction
D.trench formation
The correct option is (B)mantle convection
Tectonic plates at the earth's surface move because of the intense heat in the Earth's core. this heat causes molten rock in the mantle layer to move. It moves in a pattern called a convection cell and producing a movement called mantle convection which is the slow creeping motion of Earth's solid silicate.
2 The greater the force applied on an object, the greater it's acceleration
3 You can find the mass of an object if you know it's acceleration and the forces acting on it
4 Force is equal to the product of mass and acceleration
Answer:
1. The mass will change depending on the force.
Explanation:
We know that the newton's second law of motion gives the relation between the mass (m) of an object, force (F) applied and the corresponding measure of acceleration (a) of the object. This can be expressed in the form of an equation:
F = ma
Thus force is the product of mass and acceleration. Using this equation we can derive mass of an object, if acceleration and force values are known.
In the given equation, mass is a constant value and mass will not change in any case. Therefore force is directly proportional to amount object will be accelerated. With the increase in force applied on object, amount the object accelerated will increase and vice versa
-32.7° below the horizontal.
What is the normal force on the cart?
Answer:
The "normal force" on the "cart" 63.893 N.
Explanation:
To find normal force on the cart, use the equation
Normal force = mg + F sinx,
“m” being the object's mass,
“g” being the acceleration of gravity,
“x” being the angle of the cart
Given values
M = 7.33 kg
F = 14.7 N
Substitute the values in above equation
Normal force = (7.33 × 9.8) + 14.7 sin(-32.7°)
Normal force = 71.834 + 14.7 × (-0.5402)
Normal force = 71.834 - 7.94094
Normal force = 63.893 N
The "normal force" on "the cart" 63.893 N.
The normal force on the cart is 79.7 N
Explanation:
In order to find the normal force, we have to analyze the forces acting on the cart on the vertical direction.
In the vertical direction, we have the following forces:
The weight of the cart, downward, of magnitude , where m is the mass of the cart and g is the acceleration of gravity
The normal force on the cart, upward, we indicate it with N
The component of the pushing force acting in the vertical direction, downward, of magnitude , where F is the magnitude of the force and is the angle of the force with the horizontal
Therefore, the equation of the forces on the cart in the vertical direction is:
where the net force is zero since the cart is balanced in the vertical direction. We have:
We take the angle as positive since we are already considering the downward direction in the equation.
Substituting and solving for N, we find the normal force:
Learn more about forces:
B. Pushing a wheelbarrow
C. Lifting weights