b. mildly
c. highly
d. The name of the element is needed to figure this out.
Answer:The correct answer is C. Highly
Explanation:
its correct because I got it correct on my test sooo..yuup.!
-hope this helps.!!
Balance the equation and state which substance is oxidised and which is reduced
Explanation:
To balance the chemical equation for the extraction of iron from iron(III) oxide using carbon, you need to ensure that the same number of each type of atom appears on both sides of the equation. Here's the balanced equation:
2Fe₂O₃ + 3C -> 4Fe + 3CO
Now, let's determine which substance is oxidized and which is reduced:
1. Iron (Fe) undergoes a change in oxidation state from +3 in iron(III) oxide (Fe₂O₃) to 0 in elemental iron (Fe). It is reduced because it gains electrons, going from a higher positive oxidation state to zero.
2. Carbon (C) in carbon (C) undergoes a change in oxidation state from 0 to +2 in carbon monoxide (CO). Carbon is oxidized because it loses electrons and goes from an oxidation state of 0 to +2.
So, in this chemical reaction:
- Iron is reduced (it gains electrons).
- Carbon is oxidized (it loses electrons).
molecules of water are
there in 1g of water CH₂)
Answer:
3.3345 x 10^22
Answer: 484.94 K
Explanation:
T2 = T1 X V2 / V1
Temperature must be in kelvin so 543 + 273.15 =816.15
816.15 X 51.1 / 86
Answer: We can use the combined gas law to solve this problem:
(P₁V₁/T₁) = (P₂V₂/T₂)
where P is pressure, V is volume, and T is temperature in Kelvin.
We know that P₁ = P₂ (the pressure is assumed to be constant), and we are given V₁, T₁, and V₂. We can solve for T₂:
(P₁V₁/T₁) = (P₂V₂/T₂)
T₂ = (P₂V₂/T₁) * (T₁/P₁V₁)
We need to convert the initial temperature from Celsius to Kelvin:
T₁ = 543 + 273 = 816 K
Substituting the values:
T₂ = (1 atm * 86 mL / 816 K) * (51.1 mL / 1 atm * 86 mL)
T₂ = 0.0629 * 51.1 * 1000 = 3217 K
Therefore, the marshmallow would need to be heated to a temperature of 3217 K for its volume to change from 86 mL to 51.1 mL.
Enjoy (:
Henri Becquerel was studying properties of x-rays