Bubba can mow a field in 8 hours. If Skeeter helps, they both can do it together in 3 hours. How long would it take Skeeter to mow the field by himself?

Answers

Answer 1
Answer:
When they work together, they do  1/3 of the job in one hour.

                   (Bubba) + (Skeeter) = 1/3 job/hour    

Subtract 'Bubba'
from each side:            Skeeter  =  (1/3 job/hour) - (Bubba)

Bubba, working alone, does  1/8 of the job in one hour.

                                      Skeeter  =  (1/3 job/hour) - (1/8 job/hour)

Can you subtract 1/8 from 1/3 ?

Before you can subtract, you'll need a common denominator.
I've got a nice one here . . .  24 .

                   1/3  =  8/24
                   1/8  =  3/24                                                         

                   Skeeter  =  (1/3 job/hour) - (1/8 job/hour)

                                  =  (8/24 job/hour) - (3/24 job/hour)

                                  =        5/24 job/hour .

Skeeter mows at the rate of  5/24 field/hour.

The other way to look at that is:     24/5 hour/field  =  4.8 hours .

Check:

         Bubba:     1/8     field per hour  =  0.125
         Skeeter:  1/4.8  field per hour  =  0.208333...     

         Together:                        (0.125 + 0.208333)

                                             =  0.333... field per hour

                                             =    3 hours/field .                  yay!

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Of 10 students surveyed in a school , 7 picked Summer as their favorite season. If the school has 350 students. How many can be expected to perfer summer?

Answers

Answer:

The expected number of students to prefer summer=245

Step-by-step explanation:

Step 1

Determine the number of students that prefer summer as their favorite season, and the sample size

number that prefer summer=7

sample size=10

Step 2

Determine the probability of a student picking summer as their favorite season as shown;

Probability=number that prefer summer/sample size

Probability=7/10=0.7

Step 3

Determine the total number of students out of the total population that can be expected to prefer summer as follows;

Expected number of students=probability×total number of students

where;

probability=0.7

total number of students=350

replacing;

Expected number of students=(0.7×350)=245

The expected number of students to prefer summer=245

Lourdes is listening to an audio book that is 9 hours long. She has listened for 6 1/6 hours so far. How many hours of listening time are left.

Answers

9 - 6 1/6 = 
= 2 5/6 hours = 2 hours 50 minutes
Answer:
2 5/6 hours of listening time are left.
Thank you. 

Find the slope of the line that passes through the points (-10,-9)and (-10,8).

Answers

the slope/gradient formula is
(y₂ - y₁) = m(x₂ - x₁)
Plug in the coordinates to find the slope
(-10,-9) and (-10,8)
y₂ = 8                      y₁ = -9
x₂ = -10                   x₁ = -10

(8 -(-9) = m(-10-(-10)
(8 + 9) = m(-10 + 10)
(17) = m(0)
divide by 0
(17)/(0) = m
Now, this is a math error, therefore, we cannot find the slope which has the same x - value, which, in this example is, -10

Need help on question 13 with work and answer Can you guys check if 12 and 14 are also correct plz

Answers

13.
so out of the pool houses, how many have a hot tub
21/38=0.552=55% aprox

answer is 55%

12 is correct

14 technically, it 0 and -3, -3 could also be correct if you count the negativer root

3x+9
-------- how do I solve this?
4x+12

Answers

Answer :  (3x+9)/(4x+12) \n =3(x+3)/4(x+3) \n =3/4 \n (=0.75)
Put common terms in evidence and simplify:

\boxed{(3x+9)/(4x+12)=(3(x+3))/(4(x+3))=(3)/(4)}

Simplify by factoring. Assume that all expressions under radicals represent nonnegative numbers. √(96x^2y)


Rewrite without rational exponents, and simplify, if possible. 

( x^(4) y^(4) )^(1/3)

Answers

√(96x^2y)=√(16\cdot6\cdot x^2\cdot y)=√(16)\cdot\sqrt6\cdot√(x^2)\cdot√(y)\n\n=4\cdot\sqrt6\cdot x\cdot√(y)=4x√(6y)

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\left(x^4y^4\right)^(1)/(3)=\left(x^4\right)^(1)/(3)\left(y^4\right)^(1)/(3)=x^{4\cdot(1)/(3)}y^{4\cdot(1)/(3)}=x^(4)/(3)y^(4)/(3)=x^{1+(1)/(3)}y^{1+(1)/(3)}\n\n=x^1x^(1)/(3)y^1y^(1)/(3)=x\sqrt[3]{x}\cdot y\sqrt[3]y=xy\sqrt[3]{xy}