The ratio of the weight of an object on Planet A to the weight of the same object on Planet B is 100 to 3. If an elephant weighs 3800 pounds on Planet A, find the elephants weight on Planet B

Answers

Answer 1
Answer:

Answer:

the elephants weight on Planet B is 114.first you divide 3800 by 100 it gives you 38 then multiply 38 times 3 it gives you 114.the answer of the question is 114. you have to use unit rate or the whole enchilada method.

Step-by-step explanation:


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Which of the following systems of inequalities has point D as a solution?​

Answers

Answer:

The answer is A

Step-by-step explanation:

For two weeks, Mario recorded the color of the traffic light at the intersection of Main Street and North Avenue as his bus approached the intersection. He created this frequency table. What data did he collect to create this frequency table? A. green, red, red, red, red, red, green, red, red, yellow
B. red, red, red, yellow, red, red, green, red, red, yellow
C.red, red, red, red, red, red, green, red, red, yellow
D.red, red, green, red, red, red, green, red, red, yellow

frequency table:
Red: 7
Green: 2
Yellow: 1
Total: 10

Answers

A. Because the data in the frequency table matches the data in A.
A because that's the only one with matching data.

What is the greatest common factor of 8m, 36m^3 and 12

Answers

Answer: 4

Step-by-step explanation:

The given expressions :8m,\ 36m^3\ and\ 12

The prime factorization of 8m is given by :-

8m=2*2*2* m

The prime factorization of 36m^3 is given by :-

36m^3=2*2*3*3* m* * m

The prime factorization of 12 is given by :-

12=2*2*3

We can see that the greatest common factor of 8m,\ 36m^3\ and\ 12 is 2*2=4

Thus, the  greatest common factor of 8m,\ 36m^3\ and\ 12=4

8m=2*2*2*m
36m^3=2*2*3*3*m*m*m
12=2*2*3

gcf=2*2
answer is 4

A bee flies at feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for ​minutes, and then flies directly back to the hive at feet per second. It is away from the hive for a total of minutes. a. What equation can you use to find the distance of the flowerbed from the​ hive? b. How far is the flowerbed from the​ hive?

Answers

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

A bee flies at 12 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 14 ​minutes, and then flies directly back to the hive at 8 feet per second. It is away from the hive for a total of 18 minutes. A. Write the equation. Let d be the distance of the flowerbed from the hive. B. how far away is the hive from the flower bed.

First we need to calculate the time taken by the bee to fly to a flowerbird to its hive using the formula;

Speed = Distance/Time

Time = Distance/Speed

If a bee flies at 12 feet per second directly to a flowerbed from its hive, then the time taken by the bee is expressed as;

t1 = d/12 ....... 1

If the bee then flies directly back to the hive at 8 feet per second, the time taken by the bird will be:

t2 = d/8 ....... 2

Total time taken by the bee to and fro will be the sum total of both times;

t1+t2 = d/12+d/8

t11+t2 = 2d+3d/24

t1+t2 = 5d/24 ........ 3

If the bee stays at the bee stays at the flowerbed for 14 ​minute and away from the hive for 18minutes, the total time used by the bird during the journey will be 18-14 = 4 minutes

converting 4 minutes to seconds

4 minutes = 4*60 = 240seconds

The equation that can be used to find the distance of the flowerbed from the​ hive is gotten by equating equation 3 to  the total time used by the bird during the journey i.e;

5d/24 = 240

5d = 24*240

5d = 5760

b) To know how far is the flowerbed from the​ hive, we will solve the resulting equation in a for the value of d as shown

Given 5d = 5760

Divide both sides by 5

5d/5 = 5760/5

d = 1152ft

Hence the distance of the flowerbed from the​ hive is 1152ft

Find the area of the polygon with the coordinates (1, 2), (3, 2), (3, 0), and(1,0).
2 sq. units
8 sq. units
4 sq. units
16 sq. units

Answers

Answer:

4 sq. units

Step-by-step explanation:

Since the polygon has 4 vertices, hence the polygon is a quadrilateral with four sides and four angles.

We can see that for this polygon, opposite sides are parallel and equal to each other.

To find the area of the polygon, we have to first get the length of the polygon and then the width of the polygon, hence:

The length is the distance between (1, 2) and (3, 2):

length=√((3-1)^2+(2-2)^2) =2\ units\n

The breadth is the distance between (3, 2) and (3, 0):

length=√((3-3)^2+(0-2)^2) =2\ units\n

Since length = breadth, hence this is a square.

Area= length * breadth = 2 * 2 = 4 sq. units

We are interested in the dimensions of a certain square. A rectangle has length twice the side of this square and width three units less than the side of this square. If the two areas are equal, what are the square's dimensions (w x h)?

Answers


We don't need the length AND width of the square.  One number
will be enough for an answer, because all sides of a square have
the same length.  Let's call that number ' M ' (for 'mystery number').

-- The area of the square is  M² .

The question says that ...
-- The length of the rectangle is  2M .
-- The width of the rectangle is  (M - 3) .

Therefore ...
-- The area of the rectangle is  (2M)(M - 3)  =  2M² - 6M .

The question also says that ...
-- The areas of the square and the rectangle are equal:

So                                            2M² - 6M = M²

Subtract  M²  from each side:    M² - 6M = 0

Divide each side by  M :            M  -  6  =  0

Add  6  to each side :                 M  =  6 .


Check:

Assume ... Side of the square = 6

Then ...
Area of the square = 6² = 36 .
Length of the rectangle = (6 x 2) = 12
Width of the rectangle = (6 - 3) = 3
Area of the rectangle = (12 x 3) = 36

                 36  =  36                  yay!