In the drawing below, PQ is parallel to ST. Triangle PQR is similar to triangle TSR. Which statement about the sides is true?
In the drawing below, PQ is parallel to ST. Triangle - 1

Answers

Answer 1
Answer:

Answer:

PR corresponds to TR

Step-by-step explanation:

<Q and <S are pair of alternate angles [since PQ is parallel to ST]

<Q = <S [since they are alternate angles]

So, PR corresponds to TR [since they are opposite sides of alternate angles and ΔPQR is similar to ΔTSR]

Answer 2
Answer:

Answer:

PR corresponds to TR.

Step-by-step explanation:

Its the second choice:

PR corresponds to TR.

This is because they are opposite equal angles ( < Q and <S).


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For a field trip 13 students rode in cars and the rest filled three buses. How many students were in each bus if 106 students were on the trip? There were _________ students on each bus.

Answers

For the field trip, there were 31students on each bus.

How to solve the number of student on each bus

Given information:

Total number of students on the field trip: 106

13 students rode in cars.

We need to find out how many students were in each bus.

Calculate the number of students who rode in cars.

Number of students in cars = Total students - Number of students in buses

Number of students in cars = 106 - 13

Number of students in cars = 93

Determine the number of students in each bus.

Number of students in each bus = Total students in buses / Number of buses

Number of students in each bus = 93 / 3

Number of students in each bus = 31

So, there were 31 students on each bus.

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Answer: 31

Step-by-step explanation:  106 -13 = 93

                                               93 divided by 106 = 31

                                                 

Lucas is making accessories for the soccer team, he uses 685.85 of fabric on headbands for 41 players and 2 coaches. He also uses 353.83 inches of fabric on wristbands for the just the players. How much fabric was used on a headband and wristband for each player?

Answers

15.95 inches fabric was used on headband and 8.63 inches fabric was used on wristband of each player.

Step-by-step explanation:

Fabric used for headbands = 685.85 inches

No. of players = 41

No. of coaches = 2

Total = 41+2 = 43

Fabric used for one headband = (Fabric\ used)/(Total)

Fabric used for one headband = (685.85)/(43) = 15.95\ inches

Fabric used for wristbands = 353.83 inches

No. of players = 41

Fabric used for one wristband = (Fabric\ used)/(No.\ of\ players)

Fabric used for one wristband = (353.83)/(41) = 8.63\ inches

15.95 inches fabric was used on headband and 8.63 inches fabric was used on wristband of each player.

Keywords: division, unit rate

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Can somebody help me with number four plz

Answers

Step-by-step explanation:

3.

$30.32/8 = $3.79 per gallon

4. (a)

Weight of single gallon = 41.7/5 = 8.34 pounds

(b)

Weight of 70 gallons = 70*8.34 =

583.8 pounds

What is the height of a rectangular prism with a base of 147cm and a volume of 1323cm

Answers

What is the meaning of science

The vertices of a quadrilateral ABCD are A(4, 8), B(10, 10), C(10, 4), and D(4, 4). The vertices of another quadrilateral EFCD are E(4, 0), F(10, -2), C(10, 4), and D(4, 4). Which conclusion is true about the quadrilaterals? (5 points)A.The measure of their corresponding angles is equal.
B.The ratio of their corresponding angles is 1:2.
C.The ratio of their corresponding sides is 1:2
D.The size of the quadrilaterals is different but shape is same.

Answers

ABCD are A(4, 8), B(10, 10), C(10, 4), and D(4, 4).
EFCD are E(4, 0), F(10, -2), C(10, 4), and D(4, 4). 

After plotting the points, the conclusion that is true about the quadrilaterals is "
A.The measure of their corresponding angles is equal." ABCD is just a reflection of EFCD.

Answer:

A.The measure of their corresponding angles is equal.

Step-by-step explanation:

I got it right on a FLVS test

Using the laws of indices, simplify the following:-

√h × √h³ =

Answers

\sqrt h\cdot√(h^3)=\nh^{(1)/(2)}\cdot \left(h^3\right)^{(1)/(2)}=\nh^{(1)/(2)}\cdot h^{(3)/(2)}=\nh^{(1)/(2)+(3)/(2)}=\nh^{(4)/(2)}=\nh^2

or other way

\sqrt h\cdot√(h^3)=\n √(h^4)=\n √((h^2)^2)=\n |h^2|=\n h^2