Answer:
10 dinners
Step-by-step explanation:
We solve using the Least Common Multiple Method.
We are told:
Pasta is sold in packages of 10 boxes Sauce is sold in packages of 2 jars.
We find the Multiples of 2 and 10
Multiples of 2:
2, 4, 6, 8, 10, 12, 14
Multiples of 10:
10, 20, 30
Therefore,
LCM(2, 10) = 10
The least number of dinners that Manny can make without any supplies leftover is 10 dinners
For serving 8 peoples, 4 pounds of beef is needed.
Given is that a recipe for stew calls for 2 pounds of beef to serve 4 people. Gina wants to serve 8 people.
It is given that it requires 2 pounds of beef to serve 4 people.
For 1 people, it will take (2/4) or 1/2 pounds of beef.
So, for serving 8 peoples, (1/2) x 8 or 4 pounds of beef is needed.
Therefore, for serving 8 peoples, 4 pounds of beef is needed.
To solve more questions on functions, expressions and polynomials, visit the link below -
#SPJ6
Answer:
Step-by-step explanation:
The given expression is
The exponent property
Applying this exponent property, we have
Now, the given numeric values are x = 9, y= 8, and z= 16
On substituting these values in the simplified expression, we get
This can be further simplified by writing
Now, applying the product rule of exponent:
-4x+7y=-4
b) Determine x so that the volume of the box is at least 450 cubic inches.
c) Determine x so that the volume of the box is maximum.
The volume of the box as a function of x V(x) = x ( 60 -2x )( 15-2x )
The volume of the box as a function of x inches 0.55 inches ≤ x ≤ 6.79
The volume of the box is maximum x ≥ 6.79 inches
Given ,
The box with no top that is to be made by removing squares of width x
The corners of a 15-in by 60-in piece of cardboard.
V(x) = x ( 60 -2x )( 15-2x )
Where : x = height , ( 60 - 2x ) = length , ( 15 -2x ) = width
The volume of the box as a function of x is V(x) = x ( 60 -2x )( 15-2x )
The volume of the box ≥ 450 inches
V(x) = x ( 60 -2x )( 15-2x )
The volume of the box is at least 450 cubic inches.0.55 inches ≤ x ≤ 6.79 inches
For more information about Volume of the square click the link given below
Answer:
a) V(x) = x ( 60 -2x )( 15-2x )
b) 0.55 inches ≤ x ≤ 6.79 inches
c) x ≥ 6.79 inches
Step-by-step explanation:
Given data:
No top, cardboard dimensions ; 15-in by 60-in
a) A function for the volume of the box as a function of x the Volume can be represented by this function below
= V(x) = x ( 60 -2x )( 15-2x )
where : x = height , ( 60 - 2x ) = length , ( 15 -2x ) = width
b) determine x so that the volume of the box ≥ 450 inches
450 = x( 60 - 2x ) ( 15 -2x ) ( solving the equation )
0.55 inches ≤ x ≤ 6.79 inches
c ) The value of x for which volume of the box is maximum
will be x ≥ 6.79 inches