Find (2x^2+2)+(x^2-4)-(3x^2+1)
Answers
3x^2-1
6x^2-3
-3
6x^2

Answers

Answer 1
Answer:

Answer:

-3

Step-by-step explanation:

(2x^2+2)+(x^2-4)-(3x^2+1)

Distribute the minus sign

(2x^2+2)+(x^2-4)-3x^2-1

Combine like terms

2x^2+x^2-3x^2-1+2-4

0x^2 -3

-3

Answer 2
Answer:

Answer:

the answer is -3

Step-by-step explanation:

I took the test


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Help please with this, ASAP!

Answers

Answer:

a_(n)=12n-8

Step-by-step explanation:

We have been given a recurrence relation a_(n+1)=a_(n)+12 and the first term of the sequence a_(1)=4.

We can rewrite the given recurrence relation as: a_(n+1)-a_(n)=12

We know that if difference between two consecutive terms is always constant, the sequence is called an arithmetic sequence. So we are dealing with an arithmetic sequence with first term as 4 and common difference as 12.

We can therefore, write an explicit formula for nth terms of the sequence as.

a_(n)=a_(1)+(n-1)d\na_(n)=4+(n-1)(12)\na_(n)=4+12n-12\na_(n)=12n-8\n

This is the required explicit function rule for the given sequence.

A water bottle holds 3 1/3c of water. A bowl holds 2 1/4 times the amount in the water bottle.How much water does the bowl hold?

Express your answer as a mixed number in the simplest form.

Enter your answer in the box.

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