The equation for the reaction is is 2H2O = 2H2 + O2
Ratio of H to O in water = 2:1
Molar mass of water = 2*1.008 + 15.999 = 18.015
18.015 g gives 2*1.008 hydrogen
20 gives 2* 1.008 * 20 / 18.015
= 2.24 g hydrogen to the nearest hundredth.
Answer:
Explanation:
The missing incomplete resonance structure is attached in the image below. From there, we can see the addition of the nonbonding electrons and its' formal charge which makes the resonance structure a complete resonance structure. The others two resonance structure that can be derived from the complete structure is also shown in the image. Out of these three structures, the structure that contributes most to the hybrid is the structure with the negative charge on the oxygen.
To complete the provided resonance structure, add nonbonding electrons and formal charges. Then, draw the two remaining resonance structures by distributing the nonbonding electrons and formal charges differently.
When completing the provided incomplete structure of the anion, you need to add nonbonding electrons and formal charges to make it accurate. Then, draw the two remaining resonance structures by distributing the nonbonding electrons and formal charges differently. To illustrate, let's consider the example of a nitrate ion (NO3-). The complete structure of the provided resonance form would have a double bond between the central nitrogen atom and one of the oxygen atoms, with two lone pairs on the nitrogen atom. The remaining two resonance structures would have different double bond oxygen-nitrogen combinations.
#SPJ3
The combustion of ethane yields carbon dioxide, and with 5.90 moles of ethane being reacted, it results in the production of 11.8 moles of CO2.
The question pertains to the concept of stoichiometry in chemistry, and the chemical reaction in question is a combustion reaction involving ethane (C2H6). From the balanced reaction, it is evident that 2 moles of ethane (C2H6) produce 4 moles of carbon dioxide (CO2). Therefore, if we have 5.90 moles of ethane reacting, it's a straightforward calculation to determine that this would yield twice that many moles of CO2. We simply multiply the moles of ethane by the stoichiometric ratio (4/2) to get the moles of CO2.
Example Calculation: 5.90 moles of ethane x (4 moles CO2 / 2 moles C2H6) = 11.8 moles CO2
So, when 5.90 moles of ethane are burned in an excess of oxygen, 11.8 moles of CO2 are produced.
#SPJ3
In the combustion of ethane, for every mole of ethane burned, two moles of carbon dioxide are produced. Hence, when 5.90 moles of ethane are burned, 11.8 moles of carbon dioxide are produced.
The chemical reaction given, 2C2H6(g) + 7O2(g) ⟶ 4CO2(g) + 6H2O(g), states that 2 moles of ethane (C2H6) produce 4 moles of carbon dioxide (CO2). Thus, the mole-to-mole ratio of ethane to carbon dioxide is 2:4, or simplified, 1:2. So, for every mole of ethane burned, two moles of carbon dioxide are produced.
Given that 5.90 moles of ethane are burned, we can calculate the quantity of carbon dioxide produced by multiplying 5.90 moles by 2. Hence, when 5.90 moles of ethane are burned in an excess of oxygen, 11.8 moles of carbon dioxide are produced.
#SPJ2
Answer:
Potassium (K) [First element in period 4]
Answer:
It is selective about which substances enter or leave the cell.
Explanation:
Also srry for spamming u all the time.
UwU hope this helps tho
Answer:
It is selective about which substances enter or leave the cell
Explanation:
I have learned this already
b. exothermic reaction
c. spontaneous reaction.
d. nonspontaneous reaction.
Answer:
a. endothermic reaction
Explanation:
In an endothermic reaction, heat is absorbed from the environment. This leaves the surrounding at a colder temperature compared to the system.
ΔH, the change in enthalpy is assigned a positive sign because the heat energy level of the final state is higher than that of the initial state.
Some examples are mostly dissolution substances in water.
I think your answer is 20x
The total number of drops in an 8 mL blood collection tube is obtained by dividing the volume of the tube (8 mL) by the volume of one drop (0.05 mL), resulting in 160 drops.
To find out how many drops of blood are in the blood collection tube that holds 8mL, you have to divide the total volume of the tube by the volume of one drop. Since one drop of blood is 0.05mL, the calculation is as follows:
8 mL / 0.05 mL = 160 drops of blood
So, if a blood collection tube holds 8 mL, it would contain 160 drops of blood.
#SPJ2