Which system of equations has the same solution as the system below? 2x+2y=16 and 3x-y=4

Answers

Answer 1
Answer: 4x divide 16 3x-4y it is the answer

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If f(x)=|3x-4|+2, find f (-10)

Answers

f(x)=|3x-4|+2\n\n\nf(-10)=|3\cdot(-10)-4|+2=|-30-4|+2\n\n=|-34|+2=34+2=36
f(x)=|3x-4|+2\n \n f (-10)=|3\cdot(-10)-4|+2=|-30-4|+2=|-34|+2=36

Given the figure below, find the measure of​

Answers

GHK = GHJ + JHK
GHK = 2x+10+8x-7
GHK = 10x+3
sub. x=9,
GHK = 10(9) + 3
= 90 + 3
= 93°

Answer:

angle GHJ Is 28 degrees and angle JHK is 65 degrees

Step-by-step explanation:

I was not sure exactly what you were asking for but hope that helps

Roots of a quadratic equation 3x²-x+9=0 are p and q. Value from p/q + q/p = ....?

Answers

Hello,

3x²-x+9=0
==>x²-x/3+3=0
p+q=1/3
pq=3
p/q+q/p=[(p+q)²-2pq]/(pq)=[(1/3)²-2*3]/3=[1/9-6]/3=-53/27


3x²- x + 9 = 0
also x² - (1/3)x + 3 = 0

p,q are roots so
(x - p)(x - q) = x² - (1/3)x + 3 = 0
x² - (p+q)x + pq = x² - (1/3)x + 3 = 0

compare coefficients we have
p+q = 1/3 ... (1)
pq = 3 ... (2)
(1)/(2) ... (p+q)/pq = (1/3)/3
p/q + q/p = 1/9

at a high school, the probability that a student is a senior is 0.25. the probability that a student plays a sport is 0.20. the probability that a student is a senior and plays a sport is 0.08. what is the probability that a randomly selected student plays a sport, given that the student is a senior?

Answers

Answer:

0.32

Step-by-step explanation:

We have been given that at a high school, the probability that a student is a senior is 0.25. The probability that a student plays a sport is 0.20. The probability that a student is a senior and plays a sport is 0.08.

We will use conditional probability formula to solve our given problem. P(B|A)=\frac{P(\text{A and B)}}{P(A)}, where,

P(B|A) = The probability of event B given event A.

P(\text{A and B)} = The probability of event A and event B.

P(A) =Probability of event A.

Let A be that the student is senior and B be the student plays a sport.  

P(A and B) = Probability that student is a senior and plays a sport.

P(B|A)=\frac{\text{Probability that a student is a senior and plays a sport}}{\text{Probability that a student is senior}}

Upon substituting our given values we will get,

P(B|A)=(0.08)/(0.25)

P(B|A)=0.32

Therefore, the probability that a randomly selected student plays a sport, given that the student is a senior will be 0.32.


Express Fx and Fy in terms of the length of the vector F and the angle θ, with the components separated by a comma.

Answers

Fx, Fy = F cos θ, F sin θ

Further explanation

This is a fundamental problem with vector components.

  • A vector quantity is some quantities that have the magnitude and a direction. For example, all forces or momentums are vectors.
  • Whereas, a scalar quantity only has magnitude. For example, all forms of energy are scalars.

The list below shows some recognized methods to represent a vector. i.e., a force.

\boxed{ \ \textit{\textbf{F}}, \vec{F}, \bar{F} \ }

It is possible to split one vector into two vectors. This process is called resolving and the vectors that we get are called the components of the original vector.

Vector problems can always be solved by using the mathematics of trigonometry, i.e., the functions of sine or cosine. This is particularly appropriate when resolving.

By using the cartesian coordinate system, see the attachment on how to calculate the values of either these components.

  • Horizontal component:\boxed{ \ F_x = \textit{\textbf{F}}\ cos \ \theta \ }
  • Vertical component: \boxed{ \ F_y = \textit{\textbf{F}} \ sin \ \theta \ }

Here, the angle between the vector F and the horizontal axis we call θ (theta).

As a reminder:

  • \boxed{cos \ \theta = (adjacent)/(hypotenuse)} \rightarrow cos \ \theta = (F_x)/(F) \rightarrow \boxed{F_x = F cos \ \theta}
  • \boxed{sin \ \theta = (opposite)/(hypotenuse)} \rightarrow sin \ \theta = (F_y)/(F) \rightarrow \boxed{F_y = F sin \ \theta}

Learn more

  1. Finding the acceleration between two vectors brainly.com/question/6268248
  2. A correct representation of 0.000025 in scientific notation brainly.com/question/2261308
  3. The theoretical density of platinum which has the FCC crystal structure brainly.com/question/5048216

Keywords: express Fx and Fy, in terms of the length of the vector F, and the angle θ, with the components, separated by a comma, resolving, split, horizontal, vertical, angle, theta, sine, cosine, trigonometry, cartesian coordinate system

The components of the vector F are \fbox{\begin\nF\cos\theta\end{minispace}} and \fbox{\begin\nF\sin\theta\end{minispace}}.

Further Explanation:

A physical quantity can be defined as the physical property that can be measured and have some value in numbers.  

For example- mass, amount of substance, length, time, electric current, temperature, force, light intensity, density, velocity, speed etc.

A quantity is said as a vector if it has some magnitude and direction in order to give the details regarding the quantity.

For example- Force, velocity, current density, electric field, magnetic field, displacement, acceleration, momentum etc.

A quantity is said as a scalar if it has only the magnitude in order to give the details regarding the quantity.

For example- speed, distance, current, volume, density, mass, energy, time, temperature etc.

Given:

The resultant vector is F.

The horizontal component is {\vec F_x}.

The vertical component is {\vec F_y}.

 

Concept:

Let a vector have some length F and making an angle \theta with horizontal axis.

The triangle rule of resultant vector state that when two vector is denoted by the two sides of the triangle and the magnitude and the direction is taken in the same direction then the third side of the triangle denoted by resultant vector with some magnitude and direction.

The diagram is drawn as shown in the Figure 1.

The vertical component is along y-axis and the vertical component of the vector \vec F is expressed as:

{\vec F_y}=F\sin\theta

The horizontal component is along x-axis and the horizontal component of the vector \vec F is expressed as:

{\vec F_x}=F\cos\theta

therefore, the components of the vector F are \fbox{\begin\nF\cos\theta\end{minispace}} and \fbox{\begin\nF\sin\theta\end{minispace}}.

Learn more:

1. Displacement vector https://brainly.in/question/3332823

2. Magnitude of the vector brainly.com/question/12501440

3. Magnitude of the vector brainly.com/question/11538030

Answer Details:

Grade: High school

Subject: Physics

Chapter: Kinematics

Keywords:

Express, Fx, Fy, vector, F, angle, theta, components, Fsin theta, Fcos theta.

What area is M ∆ BXF?

Answers

Answer:

DC and Maryland college park

Step-by-step explanation:

dear teachers today go through the use 16 pencils and erasers hesitate