There goes my hopes for Virtuoso rank....What are the zeros of the function y = x2 + 10x – 171, and why?
A) The zeros are x = –19 and x = 9 because in factored form, the function is y = (x – 19)(x + 9)
B) The zeros are x = –19 and x = 9 because in factored form, the function is y = (x + 19)(x – 9).
C) The zeros are x = 19 and x = –9 because in factored form, the function is y = (x – 19)(x + 9).
D) The zeros are x = 19 and x = –9 because in factored form, the function is y = (x + 19)(x – 9).
Answers
y = (x - 9)(x + 19)
x - 9= 0 x + 19 = 0
x = 9 x = -19
Answer B covers all requirements... the factored form is
y= (x + 19)(x - 9)
and the zeros are -19 and 9
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What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long?a) 9 units, 12 unitsb) 11 units, 10.2 unitsc)4.9 units, 15.8 unitsd)4.9 units, 14.2 unitse)5.2 units, 14.1 units
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0=7x^2+8x-6
2nd degree, therefor there are 2 solutions and also 2 intersections
answe is 2 times
Answers
48+40=88
88+40=128
128+50=178
Thats all i found so far in the pattern
30,40,40,50
then it drops
by 140 then adds by 30..
I dont know how else to explain it
Answers
Final answer:
The absolute maximum and minimum of a function on a given interval can be found by calculating the function's critical points and evaluating the function at these points and the interval endpoints, then comparing these values.
Explanation:
In order to find the absolute maximum and absolute minimum values of a function on a given interval, you must first find the critical points of the function within the interval. Critical points occur where the derivative of the function is equal to zero or is undefined. In this case, the derivative of f(t) = 9t + 9 cot(t/2) is f'(t) = 9 - (9/2) csc2(t/2). Set this to zero and solve for t to find the critical points. Additionally, the endpoints of the interval, π/4 and 7π/4, could be the absolute maximum or minimum, so these should be evaluated as well. Once you have found the values of the function at these points and the endpoints, compare them to determine the absolute maximum and minimum values.
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Final answer:
To find the absolute maximum and minimum values of a function, we find the critical points and endpoints. Evaluating the function at these points gives the maximum and minimum values.
Explanation:
To find the absolute maximum and absolute minimum values of a function on a given interval, we need to find the critical points and endpoints of the interval.
To find the critical points of f, we need to find where the derivative of f is equal to zero or undefined. The derivative of f(t) = 9t + 9cot(t/2) is f'(t) = 9 - 9csc^2(t/2).
Setting f'(t) = 0, we have 9 - 9csc^2(t/2) = 0. Solving this equation, we get csc^2(t/2) = 1, which means sin^2(t/2) = 1. This gives us sin(t/2) = ±1. The critical points occur when t/2 = π/2 or t/2 = 3π/2. Solving for t, we get t = π or t = 3π as the critical points.
The endpoints of the interval are π/4 and 7π/4.
Now we evaluate the function f at the critical points and endpoints:
- f(π/4) = 9(π/4) + 9cot(π/8) ≈ 6.566
- f(π) = 9π + 9cot(π/2) = 9π
- f(3π) = 9(3π) + 9cot(3π/2) = 27π
- f(7π/4) = 9(7π/4) + 9cot(7π/8) ≈ 46.607
From these evaluations, we can see that the absolute maximum value occurs at t = 7π/4 and is approximately 46.607, while the absolute minimum value occurs at t = π/4 and is approximately 6.566.
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B.12 = 9 + 3x
C.6 + 30 = 62
D.ax – by = k
Answers
ANSWER
is an example of literal equation.
EXPLANATION
A literal equation is an equation in which letters or variables are used to represent real values.
A literal equation consists of at least two letters or variables.
The first option consists of two variables but it is not an equation. It is just an expression.
The second option is not a literal equation because it consists of only one variable. This is just a linear equation in one variable. But a literal equation should have at least two variables or letters.
As for the third option, it does not even contain a variable or letter.
Answers
Answer:
Step-by-step explanation:
Alternate angles:When two lines are crossed by another line the pair of angles on opposite sides of the transversal is called alternate angles.
Theorem 1:If a transversal intersects two Parallel Lines then each pair of alternate interior angles is equal.
Theorem 2 :If a transversal intersects two lines such that a pair alternate interior angle is equal then the two lines are parallel.
SOLUTION:
Given: ∠AGE=126°
∠AGE=∠GED=126∘ [alternate interior angles]
(ii) ∠GED=∠GEF+∠FED=126∘
∠GEF + 90° =126°
(GIVEN that EF⊥CD)
∠GEF=126°−90°=36°
∠GEF=36°
(iii) ∠CEG+∠GED=180°
(GIVEN ∠GED=126∘)
∠CEG+126° =180°
∠CEG=180° −126°
∠CEG=54°
∠FGE=∠CEG= 54° (alternate angles)
B. (2, 0)
C. (0, 0)
D. (1, -4)
Answers
Answer: The correct option is (A) (2, -5).
Step-by-step explanation: We are to select the point that is on the circle described by the following equation :
Option (A) :
(x, y) = (2, -5).
We have
So, the point (2, -5) lies on the circle (i). And so, option (A) is correct.
Option (B) :
(x, y) = (2, 0).
We have
So, the point (2, 0) lies outside the circle (i). And so, option (B) is incorrect.
Option (C) :
(x, y) = (0, 0).
We have
So, the point (0, 0) lies outside the circle (i). And so, option (C) is incorrect.
Option (D) :
(x, y) = (1, -4).
We have
So, the point (2, -5) lies inside the circle (i). And so, option (D) is incorrect.
Thus, (A) is the correct option.