Regardless of the path taken, at the end of the trip Mrs. Patil will be 8.0 miles away from home. If the path taken involves a trip lasts 0.25 hours, then the average velocity over the trip is
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the answer is in fact True
Answer:
1) When <
(hence
< f ) and they are both in front of the mirror (positive), the image will be larger and inverted
2) When >
(and
< f ) such that they are both positive (in front of the mirror), the image will be smaller and inverted
3) When the image is behind the mirror, for convex mirrors and the object is in front the image will be uptight. The magnification of the image will be the ratio of the image distance to the object distance from the mirror
Explanation:
The position of an object in front of a concave mirror of radius of curvature, R, determines the size and orientation of the image of the object as illustrated in the mirror equation
Where:
f = Focal length of the mirror = R/2
= Image distance from the mirror
= Object distance from the mirror
= Image height
= Object height
is positive for an object placed in front of the mirror and negative for an object placed behind the mirror
is positive for an image formed in front of the mirror and negative for an image formed behind the mirror
m is positive when the orientation of the image and the object is the same
m is negative when the orientation of the image and the object is inverted
f and R are positive in the situation where the center of curvature is located in front of the mirror (concave mirrors) and f and R are negative in the situation where the center of curvature is located behind the mirror (convex mirrors)
∴ When <
(hence
< f ) and they are both in front of the mirror (positive), the image will be larger and inverted
When >
(and
< f ) such that they are both positive (in front of the mirror), the image will be smaller and inverted
When the image is behind the mirror, for convex mirrors and the object is in front the image will be uptight. The magnification of the image will be the ratio of the image distance to the object distance from the mirror.
Answer:
4.8 m
Explanation:
A transverse wave is a wave in which the oscillation of the particles occur in a direction perpendicular to the direction of motion of the wave.
The amplitude of a transverse wave is the maximum displacement of the wave with respect to the equilibrium position.
The crest of a wave is the position of maximum displacement on the positive side, while the trough of a wave is the position of maximum displacement on the negative side.
This means that the amplitude of a wave is equal to the distance between a crest (or a trough) and the equilibrium position.
Therefore, we have:
where:
d is the distance between the top of a crest and the bottom of a trough
A is the amplitude of the wave
Here we have:
A = 2.4 m
So, we find