A. from the air in the freezer to the air in the refrigerator
B. from the hamburger to the air in the refrigerator
C. from the air in the refrigerator to the hamburger
D. from the hamburger to the air outside the refrigerator
Amplitude
Hertz
Period
Second
The easiest way to answer this question is by realizing there are relating the velocities of the two cars. To tackle this problem, you have to understand the picture. Car 1 travels at 35m/s and Car 2 travels at 25m/s. Based on relative velocities, we can understand that Car 1 travels 10m/s faster than Car 2 every second. So we can interpret Car 1's relative velocity to Car 2 as 10m/s. Car 1 needs to travel 10m/s till a point of catching up to Car 2 which is 462m away.
v = 10m/s
d = 462m
v = d/t
(10) = (462)/t
t = 46.2s
So it takes 46.2 seconds for Car 1 to catch up to Car 2, but the question is asking how far does Car 1 travel to catch up. So we have to use Car 1's velocity and not the relative velocity:
v = 35m/s
v = d/t
(35) = d/(46.2)
d = 1617m
Car 1 traveled a total distance of 1617m.
-- You are 462 meters behind.
-- You're gaining on him at the rate of (35m/s - 25m/s)= 10 m/s.
-- At that rate, it'll take you (462m / 10m/s)= 46.2 seconds to over take him.
-- During that time, you'll cover (46.2s x 35m/s)= 1,617 meters.