Explain the latency heat during a phase change of a substance. What does this look like on a heating curve?

Answers

Answer 1
Answer:

Answer

Latency heat is that heat which is either released or absorbed when a substance changes its physical state at constant temperature eg. from solid to liquid at the melting point or from liquid to gas at boiling point.

Explanation

The change of phase always occurs with a change of heat. However the temperature does not change because that heat energy is used to overcome cohesive forces between molecules of that substance, no part of heat energy is used to increase the kinetic energy of the molecules. Similarly, heat energy is released and molecules of that substance comes closer but temperature doesn't decrease. So its temperature will not rise/decrease since the kinetic energy of molecules remains the same.

What does this look like on a heating curve?

It is a horizontal line along x-axis.


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Which statement describes characteristics of a concave lens? A concave lens diverges light and curves inward. A concave lens diverges light and curves outward. A concave lens converges light and curves inward. A concave lens converges light and curves outward.

Answers

The correct answer is

A concave lens diverges light and curves inward.

A picture of a concave lens and the ray diagram produced by it can be seen in attachment. As it can observed, the concave lens (also called diverging lens) is wider at the edges and narrow at the centre (so, it curves inward), and it can also be seen that the lens diverges the incoming light rays.


A concave lens diverges light and curves inward is the statement which

describes its characteristics.

What is a Concave lens?

This type of lens is used to treat short-sightedness and has at least one of

its surface curving inward. This helps it to spread out light rays so as to

ensure proper view.

It has a high degree of diffraction and is the reason why option A was

chosen as it's the most appropriate choice.

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The photos of an electromagnetic wave us 1. 5 × 10^-24 j of energy , what kind of electromagnetic waves are they ?

Answers

The electromagnetic waves with an energy of 1.5 * 10^(-24)  J are likely X-rays.

The energy of an electromagnetic wave is related to its frequency and wavelength by the equation:

E = hf = hc/λ

where:

E = energy of the electromagnetic wave

h = Planck's constant (6.626 * 10^(-34)  J s)

f = frequency of the electromagnetic wave

c = speed of light (3.00 * 10^8 m/s)

λ = wavelength of the electromagnetic wave

Solving for λ:

λ = hc/E = (6.626 * 10^(-34)  J s)(3.00 * 10^8 m/s)/(1.5 * 10^(-24)  J)

λ ≈ 4.40 * 10^-8 m

This corresponds to a wavelength of about 44 nanometers, which falls in the range of X-rays. Therefore, the electromagnetic waves with an energy of 1.5 * 10^(-24)  J are likely X-rays.

for such more question on electromagnetic Wave

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What type of faulting occurs at a continental-continental convergent boundary? Explain your answer.

Answers

when two continental plates converge, it creates mountains.

What is the difference between apparent magnitude and absolute magnitude?

Answers

Here is the difference  between apparent magnitude and absolute magnitude. When we say apparent magnitude, this is the measurement of the brightness of the star of how it appears on Earth; on the other hand, absolute magnitude is the measurement of the brightness of the star at a standard distance of 32.6 light years, or 10 parsecs. Hope this answers your question.

What happens to the acceleration of the rocket if the net force is cut in half?

Answers

Explanation:

Newton's second law of motion says that the net force is equal to the mass times acceleration:

F = ma

If the net force is halved, and the mass stays the same, the acceleration will be halved as well.

F/2 = m a/2

Venus's average distance from the sun is 0.72 AU and Saturn's is 9.54 AU. Calculate the orbital velocity of Venus and Saturn around the sun. (The mass of the sun is 1.99 X 10^30 KG. an AU is 1.50 X 10^11 M.

Answers

The orbital velocity of Venus and Saturn around the sun is 8.854 x 10^8.

What is orbital velocity?

Orbital velocity is the speed required to achieve orbit around a celestial body, such as a planet or a star.

So you can compute the force of gravity on the planet

GMm/r^2

or

(6.674 * 10^(-11))(1.99 * 10^(30))m / d^2(1.5 * 10^(11))^2

Where d is the average distance of the planet from the sun and m is the mass of the planet (I will keep these as symbols so doing Saturn and Venus will be simple substitutions into one formula in the end).

Now realize that if they are in a stable circular orbit, then this force must provide the necessary centripetal force mv^2/r or mv^2 / d(1.5 * 10^(11))

So we get:

(6.674 * 10^(-11))(1.99 * 10^(30))m / d^2(1.5 * 10^(11))^2 = mv^2 / d(1.5 * 10^(11))

The m's cancel out as does one

1/d(1.5 * 10^(11))(6.674 * 10^(-11))(1.99 * 10^(30)) / d(1.5 * 10^(11)) = v^2

Evaluating and square rooting yeilds:

v = √(((8.854 * 10^8)/d))

Now plug in 0.72 for venus and 9.54 for saturn

Venus = 35067.39 m/s

Saturn = 9633.75 m/s

Some precision was lost rounding to 8.854 x 10⁸, so if more precision is required type the whole thing from before into a calculator. Anyways the process is sound.

Learn more about orbital velocity here:

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So you can compute the force of gravity on the planet GMm/r^2
or (6.674 X 10^−11)(1.99 X 10^30)m / d^2(1.5 X 10^11)^2
Where d is the average distance of the planet form the sun and m is the mass of the planet (I will keep these as symbols so doing Saturn and Venus will be simple substitution into one formula in the end).

Now realize that if they are in stable circular orbit, then this force must provide the necessary centripetal force mv^2/r or mv^2 / d(1.5 X 10^11)

So we get:

(6.674 X 10^−11)(1.99 X 10^30)m / d^2(1.5 X 10^11)^2 = mv^2 / d(1.5 X 10^11)
The m's cancel out as does one 1/d(1.5 X 10^11)
(6.674 X 10^−11)(1.99 X 10^30) / d(1.5 X 10^11) = v^2
Evaluating and square rooting yeilds:
v = sqrt((8.854 X 10^8)/d)

Now plug in 0.72 for venus and 9.54 for saturn

Venus = 35067.39 m/s
Saturn = 9633.75 m/s

Some precision was lost rounding to 8.854 X 10^8, so if more presion is required just type the whole thing from before into a calculator.  Anyways the process is sound