Answer:
3/2=15/x
Step-by-step explanation:
Solve that and you’ll get x, which is your answer
Answer:
D
but not sure because I'm not that good
a. Had at least one of these features.
b. Had all three features.
c. Did not have any of these features.
d. Had exactly two of these features.
Answer:
Step-by-step explanation:
This will be solved using set notation according to the venn diagram attached.
Let n(U) be the total number of parks surveyed
n(C) be those that had camping = 185
n(H) be those that had hiking trails = 210
n(C∩H) be those that had camping and hiking trails = 140
n(C∩P) be those that had camping and picnicking = 125
n(C∩P'∩H') be those that had only camping = 15
n(C'∩P'∩H) be those that had only hiking trails = 20
n(C'∩P∩H') be those that had only picnicking = 35
Find the calculation in the attached file
The number of parks that had at least one of the listed features was 135.
The number of parks that had all three features was 20.
The number of parks that did not have any of these features was 165.
To determine the number of parks that had at least one of the listed features, we can add up the numbers of parks that had only camping, only hiking trails, and only picnicking. Then we subtract the parks that had two or three of these features, as they were already counted in the previous step. Doing this calculation, we get:
To find the number of parks that had all three features, we need to subtract the parks that had only camping, only hiking trails, only picnicking, or none of these features from the total number of parks (300). Doing this calculation, we get:
To determine the number of parks that did not have any of these features, we subtract the parks with at least one feature from the total number of parks (300). Doing this calculation, we get:
To calculate the number of parks that had exactly two features, we add the intersections of each pair of features and subtract the parks that had all three features. Doing this calculation, we get:
#SPJ3
Answer:
(A)
Null hypothesis: Newspaper circulation in the city per day was = 15,000 in 2010
(B)
Alternative hypothesis: Newspaper circulation in the city today is > 15,000
(C)
Type 1 Error: This is the rejection of a true null hypothesis. It is the acceptance of the alternative hypothesis when the null hypothesis is true.
(D)
Type 2 Error: This is the non-rejection of a false null hypothesis. It is the acceptance of a null hypothesis when it is false.
Step-by-step explanation:
In statistical theory, the complete absence of any of these errors is virtually impossible.
Answer:
1) x = 75°
2) x = 180° - 2×40° = 180° - 80° = 100°
3) x = 180° - 2×73° = 180° - 146° = 34°
4) x = (180° - 122°) : 2 = 58° : 2 = 29°
5) x = 90° - (180° - 80°) : 2 = 90° - 100° : 2 = 90° - 50° = 40°
Answer:
Step-by-step explanation:
- A plane is oriented in a Cartesian coordinate system such that it makes an angle of ( π / 3 ) with the positive x - axis.
- A force ( F ) is directed along the y-axis as a vector < 0 , - 4 >
- We are to determine the the components of force ( F ) parallel and normal to the defined plane.
- We will denote two unit vectors: ( ) parallel to plane and ( ) orthogonal to the defined plane. We will define the two unit vectors in ( x - y ) plane as follows:
- The unit vector ( ) parallel to the defined plane makes an angle of ( 30° ) with the positive y-axis and an angle of ( π / 3 = 60° ) with the x-axis. We will find the projection of the vector onto the x and y axes as follows:
= < cos ( 60° ) , cos ( 30° ) >
- Similarly, the unit vector ( ) orthogonal to plane makes an angle of ( π / 3 ) with the positive x - axis and angle of ( π / 6 ) with the y-axis in negative direction. We will find the projection of the vector onto the x and y axes as follows:
- To find the projection of force ( F ) along and normal to the plane we will apply the dot product formulation:
- The Force vector parallel to the plane ( ) would be:
- Similarly, to find the projection of force ( ) normal to the plane we again employ the dot product formulation with normal unit vector ( ) as follows:
- To prove that the projected forces ( ) and ( ) are correct we will apply the vector summation of the two orthogonal vector which must equal to the original vector < 0 , - 4 >
.. proven
I will mark brainliest
Answer:
32.647
Step-by-step explanation: