Answer:
OM = 411.56 ft
Step-by-step explanation:
tan 11 = 80/x
0.1944 = 80/x
x = 411.56 ft
f(x) = (x + 3)2 − 6
f(x) = (x + 6)2 + 3
f(x) = (x + 6)2 − 6
By completing the square, the second orderpolynomial in vertexform f(x) = (x + 3)² - 6 is equivalent to the polynomial in standardform f(x) = x² + 6 · x + 3. (Correct choice: B)
In this question we must change the form of the second orderpolynomial from standardform into vertexform. A common method consists in completing the square, that is, to transform part of the polynomial into a perfect squaretrinomial. Now we proceed to find the vertexform of the expression:
1) x² + 6 · x + 3 Given
2) x² + 6 · x + 9 - 6 Modulative property/Existence of additive inverse/Definition of addition
3) (x + 3)² - 6 Associative property/Perfect square trinomial/Result
By completing the square, the second orderpolynomial in vertexform f(x) = (x + 3)² - 6 is equivalent to the polynomial in standardform f(x) = x² + 6 · x + 3. (Correct choice: B)
To learn more on second order polynomials in vertex form: brainly.com/question/20333425
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Answer:
B. f(x) = (x + 3)2 − 6
Step-by-step explanation:
I just did this for "completing the square". Hope this helped!
The area of yard gets watered is 707.142 ft²
The portion between any closed figure, and the extent of region of any plane is area.
Given that sprinkler sprays 15 feet in every direction
so it will form a circle with radius of 15ft
and area of circle is πr²
where r is radius of circle
value of π is 22/7
area = π x (15)²
area = 707.142 ft²
Hence area of sprinkled region is 707.142 ft²
Learn more about Area
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The most precise term for the quadrilateral ABCD with the given vertices is; A: KITE
Let us first check for the slope of the diagonals. If they intersect at right angles, then they could be square, rhombus or kite.
Slope of diagonal AC = (5 - 1)/(7 - 3) = 1
Slope of diagonal BD = (2 - 5)/(7 - 4) = -1
Thus, slope 1/slope 2 = 1/-1 = - 1
This means they intersect at a perpendicular point.
Let us know find the coordinates of their midpoints. If they are the same, then it could be a square or a rhombus. If they are different, then it is a kite.
Midpoint of AC = (7 + 3)/2 AND (5 + 1)/2 = (5, 3)
Midpoint of BD = (7 + 4)/2 AND (2 + 5)/2 = (5.5, 3.5)
They are not the same and as such this is a kite.
Read more on properties of quadrilaterals at; brainly.com/question/2834250
Answer:
Step-by-step explanation:
Given are the vertices of a quadrilateral.
WE have to find the name of the quadrilateral
WE have slope of AC = (5-1)/(7-3) = 1
and slope of BD = (2-5)/(7-4) = -1
Since m1m2 =-1 we get
the diagonals cut at right angles
This property is special property for square, rhombus and kite only.
Let us check if diagonals bisect each other
Mid point of AC =
Mid point of BD =
Since diagonals do not bisect this is neither rhombus nor square.
Only possibility is kite
4(2x-2)-4=4(x-5)+32