Help me figure this out.

Answers

Answer 1

Answer: Let me help you,
For this question, you should know that 2 2/4 is equal to 10/4.
So we know that 10/4 is 10 times 1/4.
If Julie has 1/4-cup measuring cup, then she should use her cup 10 times to get 2 2/4 cups of raisins.
Have a good one!

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an ostritch can run at a rate of 50 miles in 60 minuites. how long would it take an ostrich to run 15 mikes

Answers

50 miles ... 60 minutes
15 miles ... x minutes

If you would like to know how long would it take an ostrich to run 15 miles, you can calculate this using the following steps:

50 * x = 15 * 60
50 * x = 900 /50
x = 900 / 50
x = 18 minutes

Result: An ostrich can run 15 miles in 18 minutes.

$\sf(50~miles)/(60~minutes) = (15~ miles)/(x~minutes)\n\n50(x) = 15(60)\n\n50x = 900\n\nx = 18$

Your answer is 18 minutes

The manager at Brandon's Furniture Store is trying to figure out how much to charge for a sofa that just arrived. If the sofa was bought at a wholesale price of $97.00, and Brandon's Furniture Store marks up all furniture by40%, at what price should the manager sell the sofa?

Answers

So, we know that the manager bought the sofa for $97.00 The manager's markup price is .40 or 40%. A markup price is the selling price that someone adds on the price that he/she bought it from.

The manager got the sofa at $97.00 and put 40% of $97.00 onto the $97.00 So, when the manager sells the sofa it will cost more than $97.00

To find the new markup price, we multiply $97.00 by 1.40 or 1.4 The reason is because 97 times 100% or 1.00 is 97. That's the original price, right? How do we add 40% of 97 to itself? We add that .4 to the original price. So, 1.00 + .40 = 1.40 or a 140%. When we do $97.00*1.4, we get $135.80 Hope this helped!

All cylinders are prisms. True or false?

Answers

It is false! Not every cylinder is a prisem.

the answer is false all cylinders are not prisms

Two ants are at a common point at time t=0, the first ant starts crawling along a straight line at the rate of 4 ft/min. Two minutes later, the second ant starts crawling in a direction perpendicular to that of the first, at a rate of 5 ft/min. How fast is the distance between them changing when the first insect has traveled 12 feet? Thank you!

Answers

I looked at this just before going to bed, and it ruined my night, worrying
about it. Then, this morning, when I actually set pencil to paper, it turned
out not to be such a vicious limbic twister.

You DO need to know how to take a chain derivative, though. I must say,
I'm surprised to see this much Calculus at the middle school level. Maybe
it's MY problem, but I just can't see a way to do it without this derivative,
so I'll just show you how I did it:

The ants begin together, and crawl out along the legs of a right triangle.

-- The first one moves at 4 ft/min, so after 't' minutes, he's 4t-ft from
the vertex. The question concerns what happens when this one has
covered 12-ft. That will happen in (12/4) = 3 minutes after he starts out.

-- The second one starts out 2-min later, and moves at 5-ft/min. So,
after 't' minutes, he's 5(t-2) ft from the vertex.

-- The distance between them is the hypotenuse of the right triangle.
The square of the distance is the sum of the squares of the legs:

D² = (4t)² + [ 5(t-2) ]²

We're actually going to need to know how far apart they are after 3 minutes,
so let's do that now.

   D² = (4 x 3)² + (5 x 1)² = (12)² + (5)² = 144 + 25 = 169

   D = √169 = 13-ft apart, after the first guy has covered 12 feet.
   We will need this shortly.

OK. Now, let's simplify the equation for the distance between them,
(as we get ready to differentiate it).

   D² = (4t)² + [ 5(t-2) ]²

   D² = 16t² + (25) (t² - 4t + 4)

   D² = 16t² + 25t² - 100t + 100

   D² = 41t² - 100t + 100

The question asks "How fast is the distance between them changing . . . ? ",
and we know that this is the derivative of 'D' with respect to 't' . It's easy to
take the derivative of the right side of the equation, but what about the derivative
of ' D² ' ?   That's the part that I'm not so sure about in middle school, so I'll just
give it to you:

   (Derivative of D²) is [ (2D) times (derivative of D) ] .

Now we can take the derivative of each side of the equation:

   (2D) x (derivative of D) = 82 t - 100 .

derivative of D = (82 t - 100) / (2D)

That's how fast the distance between them is changing at any time 't' .

After 3 minutes, we calculated 'D' earlier. It's 13-ft

   derivative of D = [ (82 x 3) - 100 ] / (2 x 13)

   = 146 /    26

   = 5.615 feet per second.

Are you confident ? Do you trust me?
I'm not confident at all, and I don't trust myself.
The best I can suggest is for you to go through this and look for my mistakes,
or better yet, sit down with your teacher and go through it for mistakes.
That'll help you think about it and understand it, even if my work is wrong.

Ok, so I'll be quantizing time here to get you the most accurate result I can give you.

What you have to know is that:

$D=\sqrt { { x }^( 2 )+{ y }^( 2 ) }$

Also:

t=time snapshot (in minutes)

x=distance first ant has travelled

y=distance second ant has travelled (perpendicular to the first ant)

D=distance between both ants

--------------------------------------

Now, when:

t=0, x=0, y=0, D=0

t=1, x=4, y=0, D=4

t=2, x=8, y=0, D=8

t=3, x=12, y=5, D=13

Now we quantize time and find the tangent line (slope) between two points on the distance vs time graph at t=3 and t=3.000001, knowing that distance is represented by feet and time is represented in minutes.

When t=3.000001, x=12.000004, y=5.000005 D=13.00000562...

Now we find the slope on the distance vs time graph between the points (3,13) and (3.000001, 13.00000562).

$m=\frac { 13.00000562-13 }{ 3.000001-3 } \n \n =\frac { 281 }{ 50 }$

So, at the point (3,13) on the distance vs time graph, the two ants are moving away from each other at approximately 5.62 feet per minute.

Notations you may require to understand problem in the attachment below.

How do you solve 2/3x+15=17? it is confusing. i have been stuck on this problem for a while...

Answers

Find the opposite of adding 15. So it would be subtracting 15. So subtract 15 on both sides. So it would have 2/3x on the left and then 2 on the other side. (2/3x=2) Now find the opposite of multiplying 2/3. It is dividing 23/3. So divide 23/3 on both sides. So multiply 2/3 times 1/2. It would equal 3. x = 3
Hope this helps. :-)

Find the missing length of the figure.

Answers

$a^(2) + b^(2) = c^(2)$

4) $16^(2) +63^(2) =4225 = c^(2)$
$c= √(4225)$

Missing length= $65cm$

5) $13 ^(2)- 5^(2) =144$
$b= √(144)=12$
$12 ^(2)+35 ^(2)=1369$
c= $√(1369)$

Missing length = $37cm$

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What is 2(x-4)+38=4x

Can someone plz help meWhat is the surface area of the figure? A. 408 ft2 B. 458 ft2 C. 545 ft2 D. 720 ft2