Answer:
1/3 is larger than 1/6
Step-by-step explanation:
To understand this Better, we take the numerator as a single room while the denominator is the number of portion the room is divided to.
Now compare a room divided into 3 portions to the same size of room divided into 6 portions.
The size of the 3 portions will definitely be bigger than the sizes of the 6 portions. ..
Or mathematically, (1/3) = 0.33333 while (1/6) = 0.16666.
SL therefore, 0 .33333 is bigger than 0.16666
Answer:1/3
Step-by-step explanation: 1/3 is 33% and 1/6 is 16%
miles.
Answer:
5 miles
Step-by-step explanation:
Think of this like a triangle. From the bottom of the tower, to the top of the tower, to the point 3 miles away, and back to the bottom of the tower.
So we already have 2 side lengths. The height of the tower, 3 miles, and the base, 4 miles. In order to find the 3rd length, the distance from the top of the tower to the point 4 miles away from the bottom, we need to apply the formula A squared + B squared = C squared.
We have A and B, (3 and 4) and we need C.
A squared (3 squared) is 9
B squared (4 squared) is 16
so 9 + 16 = C squared
9 + 16 = 25
C squared = 25
square root of 25 is 5
C = 5
The distance from the top of the tower to the point 4 miles away is 5.
By applying the Pythagorean theorem to the given problem, we find that the distance from the top of the tower to the point four miles away from the base of the tower is 5 miles.
Nimrod's problem is a classic application of the Pythagorean Theorem, which states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In this case, the height of the tower is one side of the triangle (3 miles), and the distance from the base of the tower to the point Nimrod is interested in is the other side (4 miles). The distance from the top of the tower to that point is the hypotenuse.
Applying the Pythagorean theorem, we have: (Height of the tower)² + (Distance from the base to the point)² = (Distance from the top to the point)². So, this becomes: 3² + 4² = (Distance from the top to the point)². That simplifies into 9 + 16 = (Distance from the top to the point)², or 25 = (Distance from the top to the point)².
To find the actual distance (the length of the hypotenuse), we take the square root of 25, which is 5. Therefore, the distance from the top of the tower to the point four miles away from the base is 5 miles.
Using the Pythagorean theorem (a² + b² = c²), we can find the hypotenuse:
a² + b² = c²
3² + 4² = c²
9 + 16 = c²
25 = c²
c = √25
c = 5
So the distance from the top of the tower to the point four miles away from the base is 5 miles.
#SPJ11
Answer:
3,623 R6
Step-by-step explanation:
graph of coordinate plane. Point A is at 1, 3. Point B is at 3, 1. Point C is at 3, negative 3. Point D is at negative 4, 2. Point E is at negative 1, 5. Point F is at negative 3, negative 3.
Part A: Using the graph above, create a system of inequalities that only contains points B and C in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above.
Part B: Explain how to verify that the points B and C are solutions to the system of inequalities created in Part A.
Part C: Lisa can only attend a school in her designated zone. Lisa's zone is defined by y > 2x + 5. Explain how you can identify the schools that Lisa is allowed to attend.
Answer:
Part A: We have the points A = ( 1,3 ) , B = ( 3,1 ) and C = ( 3,-3 ).
We will first find the equation of line AB and AC.
Now, the slope of AB is .
So, substituting in y = mx + b along with the point ( 1,3 ) gives,
3 = -1 + b i.e. b = 4.
So, the equation of AB is y = -x + 4.
Further, slope of AC is .
Again, substituting in y = mx + b along with the point ( 1,3 ) gives,
3 = -3 + b i.e. b = 6
So, the equation of AC is y = -3x + 6.
Using 'zero test', we get that,
y = -x + 4 gives 0 = 4, which is not true.
y = -3x + 6 gives 0 = 6, which is not true.
Hence, the solution region will be away from the origin as shown in the figure 1 below.
Thus, we get the system y>-x+4 and y>-3x+6 containing point B and C.
Part B: We have the equations y = -x + 4 and y = -3x + 6.
Substitute the points B = ( 3,1 ) and C = ( 3,-3 ) into these equations respectively, we get,
y = -x + 4 gives y = -3 + 4 i.e. y = 1
y = -3x + 6 gives y = -3 × 3 + 6 i.e. y = -9 + 6 i.e. y = -3.
Hence, points B and C are the solutions of the system in Part A.
Part C: After plotting y>2x+5, we ca see from the second figure that the points included in the shaded region are D = ( -4,2 ) and E = (-1, 5).
So, Lisa is allowed to attend the schools D and E.