The number that has a 3 with a value of 1/10 the value of the 3 in 3.01 is 0.3.
The number being asked for is one where the 3 is positioned one decimal place further to the right than it is in the number 3.01, making its value 1/10 the value of the 3 in 3.01. This is interpreted to mean the 3 is place in the tenths position, rather than in the ones position as it is in 3.01. So, the number is 0.3.
To understand why, consider that in the number 3.01, the 3 is in the ones place. Hence it has a value of 3 * 1 = 3. However, in the number 0.3, the 3 is in the tenths place, which gives it a value of 3 * 0.1 = 0.3, which is 1/10 the value of 3.
#SPJ2
the probability of rolling an even number?
0 0
O 1/6
O 1/2
O 1
answer: 1/2
Answer:
iM tHe bAd gUy
duh-
Step-by-step explanation:
ANSWER
EXPLANATION
The given equation is:
Recall that:
Or
Let
Our equation then becomes:
The factors of 3 that add up to 4 are:
This implies that:
Answer:
x = 5√2
y = 5√6
z = 5√3
ΔABC ~ ΔBDC ~ ΔADB
Step-by-step explanation:
ΔABC, ΔBDC, and ΔADB are all similar triangles to each other.
By definition of similar triangles, the corresponding sides have the same ratios.
CD from ΔBDC corresponds to BD from ΔADB, and BD from ΔBDC corresponds to AD from ΔADB. So:
CD / BD = BD / AD
10 / x = x / 5
x² = 50
x = 5√2
Since ΔBDC is right, we can use the Pythagorean Theorem to solve for y:
CD² + BD² = BC²
10² + (5√2)² = y²
y² = 100 + 50 = 150
y = 5√6
Again, since ΔΔABD is right, we can use the Pythagorean Theorem to solve for z:
AD² + BD² = AB²
5² + (5√2)² = z²
z² = 25 + 50 = 75
z = 5√3
Answer:
x² = 5×10
x = √50
x = √5²×2
x = 5√2
z² = 5² + (5√2)²
z = √25 + 50
z = √75
z = √5²×3
z = 5√3
y² = 10² + (5√2)²
y = √100 + 50
y = √150
y = √5²×6
y = 5√6
x = 5√2
y = 5√6
z = 5√3
ΔABC ≈ ΔBDC ≈ ΔADB