The __ is responsible for determining the frequency of vibration of the air column in the pool with in a wind instrumen . A. Type of reed use . B. Effective length of the tube. C humidity of the air
Answers
Answer;
B. Effective length of the tube.
Explanation;
- Most wind instruments are of either the open-open tube or the open closed tube type. Open ends of the tubes makes contact with the outside, atmospheric air.
- At an open end, when the air is disturbed in the wind instruments, the air vibrates with a variety of frequencies, however the frequencies that correspond to the natural frequencies will persist.
- Effective Length of the tube is responsible for determining the frequency of vibration of the air column in the pool with in a wind instrument.
The effective length of the tube is responsible for determining the frequency of vibration of the air column in the tube within a wind instrument.
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Disregarding air resistance, what is the speed of a ball dropped from 12 feet just before it hits the ground? (Use 1 ft = 0.30 m, and use g = 9.8 m/s2.)
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Answers
Answer:
Explanation:
The equation of force is
F = 4 sin 4 t
Compare with the standard equation
f = A sin wt
where, w is the angular frequency and A is the amplitude.
Now
w = 4 rad/s
Let the time period is T.
the relation for the time period is
the time period is defined as the time taken by the body to complete one oscillation.
So, the velocity is zero at the extreme points where the object is at time, T/4 and its odd T/2, 3T/4, 3T/2, etc.
So, the velocity is zero at time
Final answer:
To determine the position of the mass and the times when the velocity is zero in a mass-spring system.
Explanation:
To determine the position of the mass at any time, we need to solve the equation of motion for the mass-spring system. The equation is:
mx'' + kx = Fext
where m is the mass, x is the displacement of the mass from its equilibrium position, k is the spring constant, and Fext is the external force. We can solve this differential equation to find the position of the mass as a function of time.
To determine the first four times at which the velocity of the mass is zero, we need to solve for the velocity of the mass, which is given by:
v = x'
We can find the times at which the velocity is zero by finding the values of t for which x' = 0.
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B. It extended the provisions of the Pregnancy Discrimination Act.
C. It extended the provisions of Title VII to previously exempt
employers.
OD. It prohibited different wages for men and women performing the
same work.
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The main effect of the Equal Employment Opportunity Act of 1972 was option C: It extended the provisions of Title VII to previously exempt employers. This act expanded the coverage of Title VII of the Civil Rights Act of 1964 to include state and local governments, public educational institutions, and some private and public employment agencies. It aimed to address and prohibit employment discrimination based on race, color, religion, sex, or national origin by a wider range of employers and entities.
Final answer:
The main effect of the Equal Employment Opportunity Act of 1972 was C. It extended the provisions of Title VII to previously exempt
employers.
Explanation:
The main effect of the Equal Employment Opportunity Act of 1972 (EEOA) was to extend the coverage of Title VII of the Civil Rights Act of 1964 to previously exempt employers. Before the EEOA, Title VII applied only to employers with 25 or more employees, leaving smaller employers unaffected. The EEOA expanded the reach of Title VII to include employers with 15 or more employees.
This significant change aimed to combat employment discrimination on the basis of race, color, religion, gender, or national origin more comprehensively by ensuring that a broader range of employers adhered to anti-discrimination measures.
Learn more about Equal Employment Opportunity Act of 1972 here:
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The frequency of a wave is the reciprocal of its period.
A period of 0.008 sec means a frequency of
1 / 0.008 sec = 125 per sec . (125 Hz)
A wave with a period of 0.008 second has a frequency of
1 /.008 = 125 Hz
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