The value of z in the following equation 2(4z − 9 − 7) = 166 − 46 is 19. Details about solving equations can be found below.
An algebraic equation is a mathematical equation in which one or both sides is an algebraic expression, such as 2x + 7y = 3.
The following algebraic equation is given in this question; 2(4z − 9 − 7) = 166 − 46. The value of z can be calculated as follows:
8z -18 - 14 = 120
8z - 32 = 120
8z = 152
z = 152/8
z = 19
Therefore, the value of z in the following equation 2(4z − 9 − 7) = 166 − 46 is 19.
Learn more about algebraic equation at: brainly.com/question/953809
#SPJ2
The answer for dividing 5/31 by 15/23 is 23/93
The division of fractions means dividing a fraction into further equal parts.
For example, If you have three-fourth of a pizza left, and you divided each slice into 2 parts you would get a total of six slices, but this would represent six-eighths of the total pizza.
Given that, find quotient 5/31 divided by 15/23.
5/31÷15/23
We know that, when we divide two fractions, we do the reciprocal of the second fraction and multiply it by the first fraction,
5/31×23/15
= 23 / 93
Hence, the answer for dividing 5/31 by 15/23 is 23/93
Learn more about division of fractions, click;
#SPJ5
32
5
4
0
Frequency- 31 33 9 2
Based on the results, the chance that a random donor has type A blood is; 11/25
We are told that there was a survey of 75 blood donors.
Now, we want to find the chance that a random donor has type A blood. From the given table, we see that there are 33 type A blood donors. Thus;
P(donor has type A blood) = 33/75 = 11/25
Read more about Probability at; brainly.com/question/251701
#SPJ5
B.15
C.45
D.30
I really need help.
The width of the rectangle is 30 units.
To find the width of a rectangle, we need to use the formula for the perimeter of a rectangle, which is 2(length + width). In this case, we are given the perimeter as 90 and the length as 15. Plugging these values into the formula, we get: 90 = 2(15 + width).
Now we can solve for the width. First, simplify the equation: 90 = 30 + 2(width).
Then, subtract 30 from both sides: 60 = 2(width). Divide both sides by 2 to isolate the width: width = 30.
Therefore, the width of the rectangle is 30 units.
#SPJ2