How do I put this in words?

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Answer 1

Answer:

Answer: one hundred an twenty seven divided by uh hundred

Step-by-step explanation:

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What is the lateral surface area of a cube with side length 9 cm?

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$a=9cm\n\nsurface\ area:A_S=6a^2\to A_S=6\cdot9^2=6\cdot81=486\ (cm^2)$

Which expression gives the volume of a sphere with radius 8?A. 4(83)
B. (82)
C. (83)
D. 4(82

Answers

Given:
radius = 8

Volume of a sphere = 4/3 * π * r³

V = 4/3 * 3.14 * 8³
V = 1.33 * 3.14 * 512
V = 2,138.21 cubic unit

The volume of a sphere is (4/3)π(r^3)

Here r = 8

Then the expression for this sphere is 4π(8^3)/3 = 4*1.05 (8^4) ≈ 4(8^3)

You have to check the options..

If a polynomial function f(x) has roots –8, 1, and 6i, what must also be a root of f(x)?

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The polynomial given is in fourth degree with four roots. If one of the given roots is an imaginary number, in this case 6i, the missing root is its conjugate. Thus, the last unknown root of the polynomial is -6i.

Answer:

Its b on edge

Step-by-step explanation:

just took te test

3 - 24 divided by 8 + 4 square

Answers

(3-24) / (8+4)^2
it's written like this right?

(-12) / (12)^2
do the work in the parenthesis first

(-12) / (144)
then square 12

(-1) / 12
simplify by dividing the numerator and the denominator by 12

Find the value of g(5) if g(x)=x3−x.

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Answer:

g(5) = 120

Step-by-step explanation:

to evaluate g(5) , substitute x = 5 into g(x)

g(x) = x³ - x , then

g(5) = 5³ - 5 = 125 - 5 = 120

Pls help with Question 11.
I need to submit it by tmr

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Answer: 81.85 km/hr

Converting m/sec into km/hr, 25 m/sec = 90 km/hr

Average =

Time = 50/90 = 5/9 hr

next 120 km at an average speed of 80km/h

=> Time = 120/80 = 3/2 hr

last part of its journey at an average speed of 90km/h in 35 Minutes

time = 35 minutes = 35/60 hr = 7/12 hr

Distance covered = 90 * 7 /12 = 105/2 km

Total Distance = 50 + 120 + 105/2 = 435/2 km

Total time = 5/9 + 3/2 + 7/12 = ( 20 + 54 + 21) /36 = 95/36

Average speed = (435/2)/(95 /36) = 432 * 18 /95 = 81.85 km/hr

How do I put this in words? ​

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How do I put this in words?