b) between 1 kW and 10 kW
c) more than 10 kW
Please show calculations!
2. power
3. work
4. voltage
5. current
6. None of these
7. torque
(I tried 2 and 6, but they were both wrong :( )
Answer:
option 4 is the correct answer
Answer:
The specific heat capacity of the substance = 455.38 J/kgK
Explanation:
Heat lost by the substance = Heat gained by water + heat gained by the aluminum calorimeter
Qs = Qw + Qc.................... equation 1
Where Qs = heat lost by the substance, Qw = heat gain by water, Qc = heat gain by the aluminum calorimeter.
Qs = c₁m₁(T₁-T₃)................ equation 2
Qw = c₂m₂(T₃-T₂)............. equation 3
Qc = c₃m₃(T₃-T₂)............. equation 4
Where c₁ = specific heat capacity of the substance, m₁ = mass of the substance, c₂ = specific heat capacity of water, m₂ = mass of water, c₃ = specific heat capacity of aluminium, m₃ = mass of the aluminum container, T₁ = Initial Temperature of the substance, T₂ = initial temperature of water, T₃ = Final equilibrium temperature.
Substituting equation 2, 3, 4 into equation 1
c₁m₁(T₁-T₃) = c₂m₂(T₃-T₂) + c₃m₃(T₃-T₂)................. equation 5
Making c₁ the subject of equation 5
c₁ = {c₂m₂(T₃-T₂) + c₃m₃(T₃-T₂)}/m₁(T₁-T₃)............... equation 6
Where c₂ = 4200 J/kgK, m₂ = 0.285 kg, m₁ = 0.125 kg, c₃ = 900 J/kgK, m₃= 0.150 kg, T₁ = 90.5°C, T₂ = 29.5°C, T₃ = 32.0°C
Substituting these values into Equation 6,
c₁ = {4200×0.285(32-29.5) + 900×0.150(32-29.5)}/0.125(90.5-32)
c₁ = {1197(2.5) + 135(2.5)}/7.3125
c₁ = {2992.5 + 337.5}/7.3125
c₁ = 3330/7.3125
c₁ = 455.38 J/kgK.
Therefore the specific heat capacity of the substance = 455.38 J/kgK
B) load
C) wedge
D) fulcrum
**its actual a physical science question**
Answer : (D) Fulcrum.
Explanation :
It is given that Julian stands on his toes to lift his body high enough so that he can reach a book. This is the example of a second class lever.
In the second class lever, the load is between the effort and the fulcrum.
In this case, the muscles provide the input force. His weight of the foot that is lifted up is the output force and toes act as a fulcrum.
So, the correct option is (D) Fulcrum.
Answer:
D
Explanation:
EDGE 22
Answer:
The candy before was fluffy, and the candy after was compacted.
Explanation:
The cloudy cotton candy was light and fluffy due to the air incorporated in it. After Chanel made it dense, the candy became compact and heavier, as she decreased the volume and maintained or increased the amount of sugar.
The cotton candy that Chanel had originally was described as being in a cloudy shape. This suggests that it was light, fluffy, and probably had a lot of air incorporated into it, which is why it was able to maintain such a shape. After she manipulated it to make it more dense, the cotton candy would have lost its cloudy appearance. Instead, it would have become heavier and more compact, because decreasing the amount of air in it increases its density. In other words, the volume of the cotton candy has decreased, but the amount of sugar within that volume has remained the same or increased.
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