Divide p(x) = x4 + 6x3 + 7x2 − 6x − 8 by x + 4 and by x − 3 to find the remainder in each case. Make sure to use the remainder theorem.
Answers
The remainder theorem says that dividing a polynomial by
leaves a remainder of
. Here,
, then
.
Final answer:
When you divide the given polynomial by x + 4, the remainder is 0. When you divide by x - 3, the remainder is 428.
Explanation:
To divide the polynomial p(x) = x^4 + 6x^3 + 7x^2 − 6x − 8 by x + 4 and x - 3 using the remainder theorem, first you substitute the roots of the divisor into the polynomial.
For x + 4, the root is -4. Substituting -4 into the polynomial yields p(-4) = (-4)^4 + 6*(-4)^3 + 7*(-4)^2 - 6*(-4) - 8 = 0. Thus, the remainder is 0 when dividing by x + 4.
For x - 3, the root is 3. Substituting 3 into the polynomial yields p(3) = (3)^4 + 6*(3)^3 + 7*(3)^2 - 6*(3) - 8 = 428 . Thus, the remainder is 428 when dividing by x - 3.
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