Daryl draws 6 equal size rectangles to make a new, larger rectangle. The area of one of the small rectangles is 12 square cm. and the length of the small rectangle is 4 cm. What is the perimeter/area?This is for my little sister. This is 3rd grade math
Answers
If one of the small rectangles area is 12 and its side length is 4..
12/4=3
So the length and width of the small rectangle are length=4 width=3.
For the NEW rectangle take..
12*6=72
That means the NEW rectangles Area is 72 sq. cm.
To find it's Perimeter...
For 1 small triangle take 3+3+4+4=14 (P=l+l+w+w)
Since there are 6 small rectangles take 14*6=84
Thus, the perimeter of the NEW rectangle is 84 cm.
All together the Area and Perimeter of the Rectangle is...
A= 72 sq cm
and
P=84 cm
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triangle MKL is an isosceles triangle with MK congruent to ML. If Mk=7x-15, KL=4x-5, and ML=10x-42, find x and the measure of each side
It is less than 0.2.
What could this fraction be?
Answers
could be one fraction whose repeating decimal is less than 0.2 and denominator is less than 10.
What is repeating decimal?
A repeating decimal is a decimal that has a digit, or a block of digits, that repeat over and over and over again without ever ending.
According to the given question.
We have to find a repeating decimal which is less than 0.2.
And if we write it in a fractional form, its denominator will less than 10.
So, if we take a fraction or rational number . Here, the denominator is less than 10 ( 9<10).
And when we evaluate we will get a repeating decimal 0.111111111.....
Hence, could be one fraction whose repeating decimal is less than 0.2 and denominator is less than 10.
Find out more information about repeating decimal here:
#SPJ2
I hope this helped you!
Then, draw a picture and replace the width with L - 6
Then come up with the perimeter of the rectangle.
A 4L + 12
B 4L - 12
C 2(6 - L ) + 2L
D 2( L- 6) + 2L
E 12 + 2L + 2L
Answers
Answer:
B 4L- 12
D 2(L -6) + 2L
Step-by-step explanation:
Perimeter is 2w + 2l, width is 6 less that length, so substitute it for w:
2w + 2l =
2(L - 6) + 2l =
2l - 12 + 2l =
2l + 2l - 12 =
4L - 12
The answer is b and d
OL
⊥
ON
start overline, O, L, end overline, \perp, start overline, O, N, end overline
\qquad m \angle LOM = 3x - 15^\circm∠LOM=3x−15
∘
m, angle, L, O, M, equals, 3, x, minus, 15, degrees
\qquad m \angle MON = 5x - 23^\circm∠MON=5x−23
∘
m, angle, M, O, N, equals, 5, x, minus, 23, degrees
Find m\angle MONm∠MONm, angle, M, O, N:
Answers
Segments LO and ON are perpendicular, providing the required
information for the value of the sum of ∠LOM and ∠MON.
- m∠MON is 57°
Reasons:
The given parameter are;
is perpendicular to
;
m∠LOM = (3·x - 15°)
m∠MON = (5·x - 23°)
Required:
Find m∠MOM
Solution:
Given that is perpendicular to
, we have;
m∠LON = 90° by definition of perpendicular lines
m∠LON = m∠LOM + m∠MON by angle addition postulate
Therefore;
m∠LOM + m∠MON = 90° by substitution property of equality
Which gives;
(3·x - 15°) + (5·x - 23°) = 90° by substitution property
8·x - 38° = 90°
x = 16°
m∠MON = 5·x - 23°
m∠MON = 5 × 16° - 23° = 57°
- m∠MON = 57°
Learn more here:
Answer:57
Step-by-step explanation:
7/9-1/4 plz help i forgot how to do dis
Answers
Answer:
19/36
Step-by-step explanation:
you find a common denominator
Answer:
19/36
Step-by-step explanation:
make the fractions have a common denominator. So you would multiply the top and bottom of 7/9 by 4. you would then get 28/36. Now multiply your other fraction by 9 top and bottom and you get 9/36. now subract the top and keep the bottom the same. and voila there is your answer
Answers
Answer:
x < -2
y > 1
Step-by-step explanation:
x < -3 + y
*x + y > -1
(-3 + y) + y > -1
-3 + 2y > -1
2y > -1 + 3
2y > 2
y > 1
*x < -3 + y
x < - 3 + (1)
x < -2