What is the 10th term of the sequence 64, 16, 4,...?a. 1/1024

b. 1/256

c. 1/4096

d. 1/496

Answers

Answer 1

Answer: Each time we are dividing by 4.
Essentially, multiplying by 1/4.
Since we're multiplying, that makes this a geometric sequence!

So: Our first term is 64, and the common ratio is 1/4.
Let's plug that into the geometric sequence formula.

$a_n=a_1(r)^(n-1)$

Where a_n = the value of the nth term
a_1 = the first term, and r = the common ratio

$a_n=64(\frac14)^(n-1)$

Now that we have our equation, let's plug in 10 for n.
That way, we can solve to find $a_(10)$ , the value of the 10th term.

$a_(10)=64(\frac14)^(10-1)=\boxed{(1)/(4096)}$

Answer 2

Answer:

the answer is C. 1/4096

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324 is the same as the sum of 144 and v

How do you find the length of arc and area of sector

Answers

To do this I must first determine what fraction of the circle is represented by the central angle 30°. Since there are 360° in a full circle, I can find the fraction of a circle by simplifying . The sector represents of the circle. To find the arc length, I now need to find the circumference of the entire circle.

If an equation of the linear function in the figure above is y=mx=b, than m=

Answers

The answer to the math question you have presented above would be 0. If an equation of the linear function in the figure above is y=mx=b, then m is equal to 0. Based on the coordinates you gave me, the logical answer would be 0 because both y and x are zeros. This means that there is no slope.

If an equation of the linear function in the figure above is y = mx + b, than m = -2

Further explanation

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

m → gradient of the line

( 0 , c ) → y - intercept

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

$\large {m = (y_2 - y_1)/(x_2 - x_1)$

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

$y - y_1 = m ( x - x_1 )$

Let us tackle the problem.

Since the figure is unknown, I will assume it is as shown in the attachment.

First, let us find the equation of solid line passing through points (0 , 2) and (1, 0) by using this formula :

$(y - y_1)/(y_2 - y_1) = (x - x_1)/(x_2 - x_1)$

$(y - 2)/(0 - 2) = (x - 0)/(1 - 0)$

$(y - 2)/(- 2) = (x)/(1)$

$1 (y - 2) = -2 (x)$

$y - 2 = -2x$

$\large {\boxed {y = -2x + 2} }$

From above equation , it can be concluded that if y = -2x + 2 , then m = -2 and b = 2

Learn more

Infinite Number of Solutions : brainly.com/question/5450548
System of Equations : brainly.com/question/1995493
System of Linear equations : brainly.com/question/3291576

Answer details

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

Please answer ASAP! An explanation is a MUST REQUIREMENT in order to receive points and the Brainliest answer. Thank you.

Answers

it would be the second one because it have a bigger value

Which expression is equivalent to (9^2/5) 9/10?

Answers

Answer:69

Step-by-step explanation:

The image of a parabolic lens is projected onto a graph. The image crosses the x-axis at –2 and 3. The point (–1, 2) is also on the parabola. Which equation can be used to model the image of the lens?y = -1/5 (x – 2)(x + 3)
y = -1/3(x – 2)(x + 3)
y = -1/2 (x + 2)(x – 3)
y = 1/4 (x + 2)(x – 3)

Answers

The right answer for the question that is being asked and shown above is that: "y = -1/3(x – 2)(x + 3)." The image of a parabolic lens is projected onto a graph. The image crosses the x-axis at –2 and 3. The point (–1, 2) is also on the parabola. the equation can be used to model the image of the lens is y = -1/3(x – 2)(x + 3)

Answer:

y = - 1/2 (x + 2)(x – 3) is the right answer

Step-by-step explanation:

Hurry! You work at a campus book store and a customer needs a textbook that you do not have in stock. You can order the textbook from Campus Corner for $129.95, prior to a rebate of $9.00. Books R Us sells the same textbook for $145.00, prior to a discount of 15%. What is the percent difference in the final cost of the two items?

O 0.018%

O 0.019%

O 1.87%

O 1.90%

O 2.10%